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andreyandreev [35.5K]
3 years ago
13

Does anyone know how to fill in this diagram?

Chemistry
1 answer:
tangare [24]3 years ago
3 0

Answer:

solid to gas is sublimation

gas to solid is deposition

liquid to gas is evaporation/boiling

the rest are correct

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Peroxyacylnitrate (PAN) is one of the components
coldgirl [10]

C – 19,9%, H – 2,2%, N – 11,6%, O – x%

M=120\frac{g}{mol}

1 percentage

The entire molecule is 100% and all the components of the compound add up to 100%.

100% - 19,9% - 2,5% - 11,6% = 66,1%

The compound contains 66,1% oxygen.

2 molar masses

M_{C}=12,01\frac{g}{mol}

M_{H}=1,008\frac{g}{mol}

M_{O}=15,999\frac{g}{mol}

M_{N}=14,007\frac{g}{mol}

3 masses

The compound has a molar mass of 120g/mol. So one molecule weighs 120 g. To find out how much the percentage of a component weighs, you have to calculate it using the molar mass.

<u>carbon</u>

19,8% of 120g

m=120g*0,198\\m=23,76g

One molecule contains 23,76g of carbon.

<u>hydrogen</u>

2,5% of 120g

m=120g*0,025\\m=3g

One molecule contains 3g of hydrogen.

<u>oxygen</u>

66,1% of 120g

m=120g*0,661\\m=79,32g

One molecule contains 79,32g of oxygen.

<u>nitrogen</u>

11,6% of 120g

m=120g*0,0,116\\m=13,92g

One molecule contains 13,92g of nitrogen.

4 amount of substance

<u>carbon</u>

<u />n=\frac{23,76g}{12,01\frac{g}{mol} }\\n=1,98mol<u />

The compound contains about 2 moles of carbon.

<u>hydrogen</u>

n=\frac{3g}{1\frac{g}{mol} }\\n=3mol

The compound contains about 3 moles of hydrogen.

<u>oxygen</u>

n=\frac{79,32g}{15,999\frac{g}{mol} }\\n=4,96mol

The compound contains about 5 moles of oxygen.

<u>nitrogen</u>

<u />n=\frac{13,92g}{14,007\frac{g}{mol} }\\n=0,99mol<u />

The compound contains about 1 moles of nitrogen.

5. molecular formula

The formula results from the ratio of the amounts of substance.

n_{C} :n_{H} :n_{O} :n_{N} =2:3:5:1\\C_{2}H_{3}NO_{5}

8 0
3 years ago
when the sum 4.9965 + 2.11 + 3.887 is calculated, to how many decimal places should the answer be reported?
jarptica [38.1K]

Answer:

the correct answer is four decimal places

3 0
3 years ago
Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3
Margarita [4]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

4 0
3 years ago
The first element on the periodic table of elements is carbon.<br><br> A. True<br> B. False
ololo11 [35]

False because Hydrogen is the first

6 0
3 years ago
Read 2 more answers
What does D represent?
Vitek1552 [10]

Answer:

C. Reactants

I think soo

5 0
3 years ago
Read 2 more answers
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