Answer:
0.257M HNO3
Explanation:
The reaction of HNO3 with Ba(OH)2 is:
2 HNO₃ + Ba(OH)₂ → 2 H₂O + Ba(NO₃)₂
That means 2 moles of HNO3 reacts with 1 mole of Ba(OH)2.
51,3mL of 0.250M Ba(OH)2 are:
0.0513L ₓ (0.250mol / L) = 0.0128moles
Moles of HNO3 are:
0.0128moles Ba(OH)2 ₓ (2 mol HNO3 / 1 mol Ba(OH)2) = 0.0257mol HNO3
As these moles are in 0.100L:
0.0257mol HNO3 / 0.100L = <em>0.257M HNO3</em>
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I hope it helps!
Answer:
The oxygen will appear in the final stage if the oxygen is excess from the beginning.
Explanation:
1. C +(1/2)O2 —> CO
2. CO+(1/2)O2—> CO2
The first stage explains that the oxygen is limited and hence CO is produced.
The 2nd stage explains that if the oxygen is excess, then CO2 will be produced.
The overall reaction when oxygen is excess is given by:
C + O2 —> CO2
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ
where, t1/2 is half-life and λ is the decay constant.
t1/2 = 10 min = 0.693 / λ
Hence, λ = 0.693 / 10 min - (1)
Nt = Nο e∧(-λt)
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken
by rearranging the equation,
Nt/Nο = e∧(-λt) - (2)
From (1) and (2),
Nt/Nο = e∧(-(0.693 / 10 min) x 20 min)
Nt/Nο = 0.2500
Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
= (Nt/Nο ) x 100%
= 0.2500 x 100%
= 25.00%
Hence, Percentage of remaining nuclei is 25.00%
Answer:
a?
Explanation:cause if organism w is a fossil and organism y is a rock the rock is way older than a fossil so a
Answer:
Explanation:
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