Answer:
Spectrum 1- Biphenyl
Spectrum 2 - Benzil
Spectrum 3 - Bibenzyl
Explanation:
<u>For Benzil:
</u>
<u>
</u>The Spectrum - 2 shows this compound.The C=O and C-H bond stretching observed at following values.
<u> For Biphenyl:
</u>
<u>
</u>Spectrum - 1 shows this compound.
There are stretching vibrations from 
due to C-H stretching and C-C stretching respectively of aromatic ring only.
<u>For Bibenzyl:
</u>
Spectrum - 3 shows this compound
There are stretching vibrations at 
due to C-H stretching and C-C stretching of aromatic ring.
Along with this, stretching vibrations at 
due to C-H of alkyl.
Answer:
k = 2.17E-2 s-1
Explanation:
Initial Concentration [A]o = 0.380 M
Final Concentration [A] = 0.215 M
time, t = 26.3 s
Unit of rate constant = s-1
Rate constant = ?
The units of the rate constant depends on the order of the reaction. This is a first order reaction due to the units.
The integral rate law for a first order reaction is;
ln[A] = ln[A]o - kt
ln(0.215) = ln(0.380) - k(26.3)
ln(0.215) - ln(0.380) = - k(26.3)
- k(26.3) = -0.57
k = 0.57 / 26.3 = 0.02167
Reporting to three significant figures using E notation;
k = 2.17E-2 s-1
Is it me or is the picture not loading
Since this equation is balanced, we know that the law of conversation of mass id applied, and we could calculate easily.
Na= 2
NO3= 2
Ca= 1
<span>Cl= 1</span>
