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melomori [17]
3 years ago
6

Calcium is a group 2 element. Chlorine is a group 7 element. They form an ionic compound called

Chemistry
1 answer:
kondaur [170]3 years ago
7 0

Answer:

CaCl2

Explanation:

For every calcium there's 2 chlorine

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How many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv) nitrate to produce chromiu
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The  moles  of  chromium (iii)  nitrate  produced  is  calculated  as   follows

write  the  equation  for  reaction

 3  Pb(NO3)2  +  2 Cr  =  2 Cr(NO3)3  +  3  Pb

by  use  of  mole  ratio  between  Pb(NO3)2  to  Cr(NO3)3  which  is  3  :  2  the  moles  of  Cr(NO3)3  is therefore  
=  0.85  x2  /3  =  0.57   moles
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Getting a vaccine is safer than taking medication or undergoing surgery. True or false I
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Which alignment of the Sun, Moon, and Earth causes a lunar eclipse? А. B. C. D.​
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Calculate the gas constant, R, if 25.55 mL of hydrogen gas was collected at a barometric pressure of 0.987 atm and a temperature
gtnhenbr [62]

Answer:

354.09

Explanation:

6 0
3 years ago
The theoretical yield of NaBr from
Lapatulllka [165]

Taking into account definition of percent yield, the percent yield for the reaction is 100%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 FeBr₃ + 3 Na₂S → Fе₂S₃ + 6 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • FeBr₃: 2 moles
  • Na₂S; 3 moles
  • Fе₂S₃: 1 mole
  • NaBr: 6 moles

<h3>Moles of NaBr formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 2 moles of FeBr₃ form 6 moles of NaBr, 2.36 moles of FeBr₃ form how many moles of NaBr?

moles of NaBr=\frac{2.36 moles of FeBr_{3}x6 moles of NaBr }{2 moles of FeBr_{3}}

moles of NaBr= 7.08 moles

Then, 7.08 moles of NaBr can be produced from 2.36 moles of FeBr₃.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield for the reaction in this case</h3>

In this case, being the molar mass of NaBr 102.9 g/mole, you know:

  • actual yield= 7.08 moles× 102.9 g/mole= 728.532 grams
  • theorical yield= 7.08 moles× 102.9 g/mole= 728.532 grams

Replacing in the definition of percent yields:

percent yield=\frac{728.532 grams}{728.532 grams}x100

Solving:

<u><em>percent yield= 100%</em></u>

Finally, the percent yield for the reaction is 100%.

Learn more about

the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

percent yield:

brainly.com/question/14408642

#SPJ1

8 0
2 years ago
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