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DedPeter [7]
4 years ago
14

A civil engineer chooses to use wooden beams because they will sag before

Chemistry
2 answers:
beks73 [17]4 years ago
8 0

Answer:

APEX

Explanation:

B

wolverine [178]4 years ago
7 0

Answer:

B. choosing a material that will show warning before it fails.

Explanation:

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Carmen has a sample of matter. It is clear and smells sour. The sample is also thick but it flows when poured. Which is the best
Oksanka [162]

Answer:

it's a liquid because it flows

Explanation:

solids don't flow and rocks can be clear too like quartz

6 0
3 years ago
Read 2 more answers
Of the following, the particle generally not found in the nucleus of an atom is
netineya [11]
An electron. Electrons are found on the outer shells.
4 0
4 years ago
C-12 and C-13 are naturally-occurring isotopes of the element carbon. C-12 occurs 98.88% of the time and C-13 occurs 1.108% of t
Veseljchak [2.6K]

Answer:

c) (12×0.9889) + (13×0.01108)

Explanation:

Given data:

Percentage of C-12 = 98.89%

Percentage of C-13 = 1.108%

Atomic mass = ?

Solution:

98.89/100 = 0.9889

1.108/ 100 = 0.01108

Atomic mass = (12×0.9889) + (13×0.01108)

Atomic mass = (11.8668 + 0.144034)

Atomic mass = 12.01084

6 0
4 years ago
A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at
wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is 0.44J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of metal = ?

C_1 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 47.1 g

m_2 = mass of water = 120 g

T_f = final temperature of water = 24.5^oC

T_1 = initial temperature of metal = 99^oC

T_2 = initial temperature of water = 21.4^oC

Now put all the given values in the above formula, we get

47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC

c_1=0.44J/g^oC

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is 0.44J/g^oC).

3 0
3 years ago
Use the equation below to determine how many grams of CO are needed to react with an excess of Fe2O3 to produce 104.9 g Fe? You
patriot [66]

Answer:

1.40 * 10 ^3 g

Explanation:

7 0
3 years ago
Read 2 more answers
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