Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
Answer:
Option C = 1.72 mol
Explanation:
Given data:
Mass of KF = 100 g
Moles of KF = ?
Solution:
First of all we have to calculate the molar mass of KF.
Molar mass of KF = 39.0983 g/mol + 18.998403 g/mol
Molar mass of KF = 58. 0967 g/mol
Formula:
Number of moles = mass/molar mass
Number of moles = 100 g/ 58.0967 g/mol
Number of moles = 1.72 mol
A. potential energy.
It can't be any of the above questions. When the automobile burns gas it converts the potential energy into chemical energy which intern gets converted into mechanical energy and then into kinetic energy.
I would have thought it would be Chemical potential energy, which is referring to the energy between the bonds in the molecule.
Hoped this helped.
Ba (OH) 2 Ba(OH) 2 is a string electrolyte, determine the concentration of each of the individual in a 0.400m Ba (OH)20.400m
