All categories

4 years ago

The boiling points of some group 7A hydrides are tabulated below.

Chemistry

1 answer:

11111nata11111 [884]4 years ago

6 0

hey there!:

In the case of ammonia, the hydrogen bond is formed using the lone pair present in nitrogen and the hydrogen having δ+ charge (due to bonding with electronegative N) of another ammonia molecule. Thus the inter molecular attraction increases which in turn increases the boiling point .

Option B is the correct answer.

Hope this helps!

You might be interested in

Calculate the molarity of a solution of acetic acid made by dissolving 16.00 mL of glacial acetic acid at 25 ∘C in enough water

Soloha48 [4]

Answer : The molarity of solution is, 1.216 g/mole

Explanation : Given,

Density of acetic acid = 1.049 g/ml (standard value)

Volume of acetic acid = 16.00 ml

Volume of solution = 230.0 ml

Molar mass of acetic acid $CH_3COOH$ = $2(12)+4(1)+2(16)=60g/mole$

First we have to calculate the mass of acetic acid.

$Mass=Density\times Volume$

$Mass=1.049g/ml\times 16ml=16.784g$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of acetic acid}\times 1000}{\text{Molar mass of acetic acid}\times \text{volume of solution in ml}}$

$Molarity=\frac{16.784g\times 1000}{60g/mole\times 230ml}$

$Molarity=1.216g/mole$

Therefore, the molarity of solution is, 1.216 g/mole

7 0

3 years ago

Describe the preparation of 350 mL of 1.20 M from the commercial reagent that is 86% (w/w) and has a specific gravity of 1.71

AfilCa [17]

Supposition:

Let's use HNO₃ as the reagent, because the question does not inform which one is. The solution will differ only on the molar mass of the reagent, but the step by step solution is the same.

Answer:

To prepare this solution, first, a little of water will be added to a volumetric flask of 350 mL, then, 18 mL of the acid will be measured by a pipet, and added to the water (the acid must be added to water to avoid explosion), then more water is added until the line of the flask and the mixture is agitated.

Explanation:

First, let's determine the molar concentration (M) of the commercial reagent. The unit w/w indicates the mass of the reagent by mass of the solution (so in 100 g of solution, 86 g are of the reagent), and the specific gravity is in a unit of g/mL. The molar mass of HNO₃ is 63.01 g/mol.

So, in 1 mL (0.003 L)of the acid, the concentration is:

M = (1.71 g/mL * 1 mL * 0.86)/(63.01 g/mol * 0.001 L)

M = 23.34 mol/L

The number of moles in the dilution remains constant, so the multiplication of the concentration by the volume is constant. If 1 is the commercial reagent, and 2 the solution prepared:

M1*V1 = M2*V2

23.34*V1 = 1.20*350

V1 = 18.00 mL

So, to prepare this solution, first, a little of water will be added to a volumetric flask of 350 mL, then, 18 mL of the acid will be measured by a pipet, and added to the water (the acid must be added to water to avoid explosion), then more water is added until the line of the flask and the mixture is agitated.

6 0

4 years ago

Complex conversion between units may require using conversion factor

Lady bird [3.3K]

That is correct boi boi boi boo boi

8 0

3 years ago

What is the molar concentration of Pb+ in a solution that contains 6.73 ppm of

Katarina [22]

Answer:

2.03 × 10⁻⁵ M

Explanation:

Step 1: Given data

Concentration of Pb(NO₃)₂: 6.73 ppm = 6.73 mg/L

Step 2: Convert 6.73 mg/L to mol/L

The molar mass of 331.2 g/mol.

6.73 × 10⁻³ g/L × 1 mol/331.2 g = 2.03 × 10⁻⁵ mol/L = 2.03 × 10⁻⁵ M

Step 3: Calculate the molar concentration of Pb²⁺

Let's consider the ionization of Pb(NO₃)₂.

Pb(NO₃)₂(aq) ⇒ Pb²⁺(aq) + 2 NO₃⁻(aq)

The molar ratio of Pb(NO₃)₂ to Pb²⁺ is 1:1. The molar concentration of Pb²⁺ is 1/1 × 2.03 × 10⁻⁵ M = 2.03 × 10⁻⁵ M.

8 0

3 years ago

When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coeffici

tatuchka [14]

The values of the coefficients would be 4, 5, 4, and 6 respectively.

<h3>Balancing chemical equations</h3>

The equation of the reaction can be represented by the following chemical equation:

ammonia (g) + oxygen (g) ---> nitrogen monoxide (g) + water (g)

$4NH_3(g)$ + $5O_2(g)$ ---> $4NO(g)$ + $6H_2O(g)$

Thus, the coefficient of ammonia will be 4, that of oxygen will be 5, that of nitrogen monoxide will be 4, and that of water will be 6.

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

5 0

2 years ago