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3 years ago

What is the difference between B-cell lymphocytes and T-cell lymphocytes?

2 answers:

3 0

There are different types of B cell and T cell. both are lymphocytes, a subclass of white blood cell. the T cells are mainly used in identifying antigens and releasing chemicals which attack macrophages (big immune cells which 'eat' antigens), to destroy the antigen. B cells are used in the antibodies. When they encounter a new antigen, plasma cells and memory cells are antibodies. Formed from the division of a B cell. the memory cell remembers the antigen and which antibody to use, while the plasma cell makes the antibodies to fight a particular antigen or class of antigens.
 Hope this could help you with your question. : )

Thepotemich [5.8K]3 years ago

3 0

Answer:

Explanation:

Lymphocytes are a class of white blood cell in the body's immune system. B-cell and T-cell lymphocytes are types of lymphocytes.

There are differences between the T-cell lymphocytes and the B-cell lymphocytes. The major differences are

T-cell lymphocytes are produced in the thymus while B-cell lymphocytes are produced in the bone marrow
T-cell lymphocytes are involved in cell-mediated immunity while B-cell lymphocytes are involved in humoral immunity

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If the half-life of a sample of a radioactive substance is 30 seconds, how much would be left after 60 seconds? A. one-fourth

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Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)

We can write the above reaction in two reactions, one for oxidation and the other for reduction:

Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻ (2)

Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)

We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).

We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.

In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).

Therefore, the reducing agent in reaction (1) is lithium (Li).

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I hope it helps you!

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