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Vlada [557]
3 years ago
5

The electron cloud model is a modern theory about the structure of atoms that explains many of the atom’s behaviors. According t

o the model, scientists imagine an atom to have a large nucleus of matter in the center surrounded by tiny particles called electrons. These electrons fly so fast and unpredictably around the nucleus that just one electron can appear to be a cloud. However, individual electrons are far too small for a human to see or touch. What is a limitation of the electron cloud model theory that a law about electrons would not have?
Physics
2 answers:
Vanyuwa [196]3 years ago
7 0

Couldn't explain that electrons behaves as both particles and waves.

Gnom [1K]3 years ago
3 0

Answer:        

According to Electron cloud model, there is a negatively charged region in an atom which has probability to find an electron.

According to Bohr's model of atom, electrons reside in fixed shells around the nucleus and never enter it. But it is the limitation of the Electron cloud model that describes that it is probable that electron might be present in the nucleus. The distance is not fixed, sometimes the electron is closer and sometimes it is away.

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When a 4.60-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.30 cm. (a) If
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Answer:

a) y = 0.0075 m

b) W = 1.569 J

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See attachment for the solution

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3 years ago
A 600kg car is at rest , and then accelerates to 5n/s what is the original kinetic energy?
lubasha [3.4K]
M = 600 kg
u = 0 (as the car was at rest initially)
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7 0
4 years ago
Electromagnetic waves vary in
topjm [15]
The electromagnetic waves are types of waves which do not require medium for them to pass through to be able to travel from one location to another. The different types of electromagnetic waves therefore vary only in their wavelength and frequency. Thus, the answer is letter B. 
5 0
4 years ago
A photon detector captures a photon with an energy of 4.29 ✕ 10−19 J. What is the wavelength, in nanometers, of the photon?
serious [3.7K]

Answer :  The wavelength of photon is, 4.63\times 10^{2}nm

Explanation : Given,

Energy of photon = 4.29\times 10^{-19}J

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength of photon  = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

4.29\times 10^{-19}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}

\lambda=4.63\times 10^{-7}m=4.63\times 10^{-7}\times 10^9nm=4.63\times 10^{2}nm

Conversion used : 1nm=10^{-9}m

Therefore, the wavelength of photon is, 4.63\times 10^{2}nm

6 0
3 years ago
What is the primary difference between an ideal emf device and a real emf device?.
EleoNora [17]

Answer:

A real emf device has an internal resistance, but an ideal emf device does not.

3 0
2 years ago
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