Answer:
Mass of sodium carbonate = 33.92 g
Explanation:
Given data:
Mass of sodium hydroxide = 38 g
Mass of carbon = 28 g
Mass of sodium carbonate produced = ?
Solution:
Chemical equation:
6NaOH + 2C → 2Na + 3H₂ + 2Na₂CO₃
Now will calculate the number of moles of reactants:
Number of moles of sodium hydroxide:
Number of moles = mass / molar mass
Number of moles = 38 g/ 40 g/mol
Number of moles = 0.95 mol
Number of moles of carbon:
Number of moles = mass / molar mass
Number of moles = 28 g/ 16 g/mol
Number of moles = 1.75 mol
Now we will compare the moles of both reactant with sodium carbonate.
C : Na₂CO₃
2 : 2
1.75 : 1.75
NaOH : Na₂CO₃
6 : 2
0.95 : 2/6×0.95 = 0.32
Number of moles of sodium carbonate produced by sodium hydroxide are less so it will limiting reactant.
Mass of sodium carbonate:
Mass = number of moles × molar mass
Mass = 0.32 mol × 106 g/mol
Mass = 33.92 g
