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slega [8]
3 years ago
6

On a part time job you are asked to bring a cylindrical iron rod of density 7800 kg/m^3, length 81.2 cm and diameter 2.75 cm fro

m a storage room to a machinist. Calculate the weight of the rod, w. The acceleration due to gravity, g= 9.81 m/s^2.w= 36.9 NNow that you know the weight of the rod, do you think that you will be able to carry the rod without a cart? Yes or No?
Physics
1 answer:
Olin [163]3 years ago
8 0

Answer:

3.76188 kg

36.9040428 N

Yes

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

L = Length of rod = 81.2 cm

d = Diameter of rod = 2.75 cm

r = Radius = \frac{d}{2}=\frac{2.75}{2}=1.375\ cm

A = Area of the cylinder = \pi r^2

v = Volume = L\times A

m = Mass

Density

\rho=\frac{m}{v}\\\Rightarrow m=\rho\times v\\\Rightarrow m=\rho\times L\times A\\\Rightarrow m=7800\times 0.812\times \pi\times 0.01375^2\\\Rightarrow m=3.76188\ kg

The mass of the rod is 3.76188 kg.

As the the mass of the rod is 3.76188 kg I will be able to carry the rod.

Weight

W=mg\\\Rightarrow W=3.76188\times 9.81\\\Rightarrow W=36.9040428\ N

The weight of the rod is 36.9040428 N

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Answer:

stress

Explanation:

Common causes of chronic insomnia include: Stress. Concerns about work, school, health, finances or family can keep your mind active at night, making it difficult to sleep. Stressful life events or trauma — such as the death or illness of a loved one, divorce, or a job loss — also may lead to insomnia.

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3 years ago
(a) You short-circuit a 20 volt battery by connecting a short wire from one end of the battery to the other end. If the current
erica [24]

(a) 1.11 \Omega

When the battery is short-cut, the only resistance in the circuit is the internal resistance of the battery. Therefore, we can apply Ohm's law:

r=\frac{V}{I}

where

V = 20 V is the voltage across the internal resistance of the battery

I = 18 A is the current flowing through it

Solving the equation,

r=\frac{20 V}{18 A}=1.11\Omega

(b) 360 W

The power generated by the battery is given by the equation

P=VI

where

V = 20 V is the voltage of the battery

I = 18 A is the current

Substituting into the formula,

P=(20 V)(18 A)=360 W

(c) 360 J

The energy dissipated by the internal resistance is given by

E=Pt

where

P = 360 W is the power generated

t = 1 s is the time

Solving the equation, we find

E=(360 W)(1 s)=360 J

(d) 1.65 A

The battery is now connected to a R=11 \Omega resistor. This means that the internal resistance of the battery is now connected in series with the other resistor R: so, the total resistance of the circuit is

R_T = r+R=1.11 \Omega +11 \Omega = 12.11 \Omega

And so, the current flowing through the circuit is

I=\frac{V}{R_T}=\frac{20 V}{12.11\Omega}=1.65 A

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The power dissipated in the external resistor is given by

P=I^2 R

where

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R=11 \Omega is the resistance

Solving the equation, we find

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(f) 18.17 V

The terminals of the voltmeter are placed at the two end of the battery. The battery provides an emf of 20 V, however due to the internal resistance, some of this voltage is dropped across the internal resistance. Therefore, the actual potential difference that will be read by the voltmeter will be:

V=\epsilon - Ir =20 V -(1.65 A)(1.11 \Omega)=18.17 V

4 0
3 years ago
An egg is dropped from a building that is 61 m high.
Allisa [31]

Answer:

Initial Velocity = 0 m/s

Final Velocity = 34.6 m/s

time = 3.5 s

Explanation:

The initial velocity must be zero since, the egg must be at rest initially, before dropping.

<u>Initial Velocity = 0 m/s</u>

Now, for time we use 2nd equation of motion:

h = Vi t + (1/2)gt²

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h = Height = 61 m

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t =time = ?

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t² = (61 m)(2)/(9.8 m/s²)

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<u>t = 3.5 s</u>

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Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(3.5 s)

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