In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
KE1 = KE2
The kinetic energy of the system before the collision is solved below.
KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s.
Weight=mg
g=GM/r^2
g on venus is 0.80w as radius is kept constant
m of object is kept constant
w α g
w(venus( is 0.8w
They made me do it I don’t even know what to say I’m so sorry
Answer:
The value is 
Explanation:
From the question we are told that
The mass of the car is 
The acceleration is 
Generally the net force applied on the rope is mathematically represented as
Here W is the weight of the car which is evaluated as
=> 
=> 
Generally the net force can also be mathematically represented as
So
=> 
=>
Answer:
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