<u>ANY</u> pair of vectors can produce that resultant, as long as ...
If one of the vectors is V₁ = A i + B j . . . . . . where 'A' and 'B' are <u>any</u> two numbers,
then the other one is V₂ = -A i - B j
Answer:
Current will decrease.
Explanation:
When we increase the number of stepping in transformer, the voltage will increase as its is directly proportional to the number of turn of stepping. Thus as the voltage will increase, current will decrease. As per the equation of ideal transformer, E1 / E2 = I2 / I1
E1 and E2 are the voltages in primary and secondary winding and I1 and I2 are the current.
As the number of turns will be increased more inevitable losses will be generated that dissipates heat thus warming the primary.
Though the conservation of energy is obeyed but losses occur in this scenario hence step-up transformers cannot be used to create free energy.
Answer:
<h2>0.245cm/min</h2>
Explanation:
The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.
Using chain rule to express dV/dt;
dV/dt = dV/dr*dr/dt
dr/dt is the rate at which the radius of the gallon is increasing.
From the formula, dV/dr = 3(4/3πr^3-1))
dV/dr = 4πr²
dV/dt = 4πr² *dr/dt
500 = 4πr² *dr/dt
If radius r = 40;
500 = 4π(40)² *dr/dt
500 = 6400π*dr/dt
dr/dt = 500/6400π
dr/dt = 5/64π
dr/dt = 0.245cm/min
Hence, the radius of the balloon is increasing at the rate of 0.245cm/min
Answer:
24.325 kg m/s
Explanation:
Initial momentum, pi = 18 kg m/s
F = < -4, 12, 0>
t = 0.5 s
Let the final momentum is pf.
The magnitude of force is
According to the Newton's second law, the rate of change of momentum is equal to the force.
pf - 18 = 6.325
pf = 24.325 kg m/s
Thus, the momentum of body after 0.5 s is 24.325 kg m/s.
Answer:
9.66 m/s 15° with +y
2.59 m/s 75° with +y
Explanation:
Momentum is conserved in the y direction.
mu₁ + mu₂ = mv₁ + mv₂
u₁ + u₂ = v₁ + v₂
10 m/s + 0 m/s = v₁ cos 15° + v₂ cos 75°
10 = v₁ cos 15° + v₂ cos 75°
Momentum is conserved in the x direction.
mu₁ + mu₂ = mv₁ + mv₂
u₁ + u₂ = v₁ + v₂
0 m/s + 0 m/s = v₁ sin 15° − v₂ sin 75°
0 = v₁ sin 15° − v₂ sin 75°
v₁ sin 15° = v₂ sin 75°
v₂ = v₁ sin 15° / sin 75°
Substitute.
10 = v₁ cos 15° + (v₁ sin 15° / sin 75°) cos 75°
10 = v₁ cos 15° + v₁ sin 15° / tan 75°
10 = v₁ (cos 15° + sin 15° / tan 75°)
v₁ ≈ 9.66 m/s
v₂ ≈ 2.59 m/s
