Answer:
1.
2.
3.The results from part 1 and 2 agree when r = R.
Explanation:
The volume charge density is given as

We will investigate this question in two parts. First r < R, then r > R. We will show that at r = R, the solutions to both parts are equal to each other.
1. Since the cylinder is very long, Gauss’ Law can be applied.

The enclosed charge can be found by integrating the volume charge density over the inner cylinder enclosed by the imaginary Gaussian surface with radius ‘r’. The integration of E-field in the left-hand side of the Gauss’ Law is not needed, since E is constant at the chosen imaginary Gaussian surface, and the area integral is

where ‘h’ is the length of the imaginary Gaussian surface.

2. For r> R, the total charge of the enclosed cylinder is equal to the total charge of the cylinder. So,

3. At the boundary where r = R:

As can be seen from above, two E-field values are equal as predicted.
Answer:

Explanation:
Average speed is given by
where
is total distance and
is time.
Plugging in given values, we get:
.
Nuclei of uranium atoms split apart is . . . . <u><em>known as nuclear fission</em></u>
Overloading
Explanation:
The reason reason why the mcb of rupa's room keeps tripping is due to the fact that excessive current has being supplied to his room.
MCB stands for a miniature circuit breaker.
A miniature circuit breaker opens up the electrical circuit by switching it off when there is overloading or faulty connections.
- A MCB helps to control the flow of current and it is designed to hand certain limits of electrical voltage.
- If the MCB keeps tripping, it suggests a surge in current supplied, overloading or probably a faulty connection.
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Answer:
30
Explanation:
Assuming the velocity is 3π radians <em>per second</em>, the top will spin through an angle of ...
(3π radians/s)(20 s) = 60π radians
Since each revolution is 2π radians, that is ...
(60π radians)/(2π radians/revolution) = 30 revolutions