At atmospheric pressure, a gas will have a certain density at that pressure. Density is measured a mass divided by the volume. If you increase the pressure in a cylinder of constant mass of gas particles, you decrease the volume at which gases occupy thus from the equation density is equal to mass over volume, a volume decrease with a constant mass yields a higher density. Therefore increasing the pressure increases the density.
Answer:
This is what I know, The angle of releases changes the relationship between the horizontal and vertical components of projectile. The idea angle of release is 45 degrees, assuming there is no air resistance and take off and landing points are the same height.
Explanation:
Velocidad inicial = 20 m/s
velocidad final = 0 m/s
aceleracion = -2 m/s^2
aceleracion = (cambio de velocidad)/(cambio de tiempo)
(cambio de tiempo)= (cambio de velocidad)/aceleracion
tiempo = (-20 m/s)/(-2 m/s^2)
= 10 segundos
x = (x(inicial)) + (v(inicial))(tiempo) + 1/2(aceleracion)(tiempo)^2
x(inicial) = 0
x = (20 m/s)(10 s) + 1/2 (-2m/s^2)(10 s)^2
x = 200 m - 100 m
x = 100 m (el espacio recorrido en los dos segundos)
espero que esto te ayude! buena suerte!
Hello!
Recall the equation for momentum:
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
<u>Part 1: </u>
We can solve for the total momentum using the above equation. Let m1 represent the 0.2 kg cart, and m2 represent the 0.4 kg cart.
Since they move off together:
<u>Part 2: </u>
Using the conservation of momentum:
m2 was initially at rest, so:
<u>Part 3:
</u>
We can calculate the force by first calculating the impulse exerted on the carts.
Recall the equation for impulse:
We can use either cart, but for ease, we can use the 0.4 cart that starts from rest.
Thus:
Now, calculate force with the following:
Plug in the values:
Answer:
the ability to disolve in water is solubility