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3 years ago

What is below the Ecosystem .

Chemistry

1 answer:

Zigmanuir [339]3 years ago

8 0

Below the ecosystem is soil, granted, and bedrock. however for the ocean ecosystem has sand below it.

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Arrange the following alkyl bromides in order from most reactive to least reactive in an SN2 reaction: 1-bromo-2-methylbutane, 1

xxMikexx [17]

Primary alkyl halides tend to undergo the SN2 reaction mechanism in nucleophilic substitution since there is less steric hindrance for nucleophilic attack and the carbocations that they form are not as stable as those formed from tertiary alkyl halides.

1-bromopentane > 1-bromo 2-methylbutane > <span>1-bromo-3-methylbutane</span>> 2-bromo 2-methylbutane

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3 years ago

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1. List the seasons from longest to shortest, including the number of days in each season.

GenaCL600 [577]

Search it up bro it’s on the internet lol

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3 years ago

A container of argon with a volume of 22 ml has a pressure of 101.0 kPa.

Alexeev081 [22]

Answer:

The new pressure is 44.4 kPa.

Explanation:

We have,

Initial volume, $V_1=22\ ml$

Initial pressure, $P_1= 101.0\ kPa$

It is required to find the new pressure when the volume is increased to 50 ml. The relationship between pressure and volume is known as Boyle's law.

$PV=k\\\\P_1V_1=P_2V_2$

$P_2$ is final pressure

$P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa$

So, new pressure is 44.4 kPa.

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3 years ago

5. How much heat (in calories) is absorbed by a reaction when

Wewaii [24]

Answer:

1.2 × 10⁴ cal

Explanation:

Given data

Mass of water (m): 300 g

Initial temperature: 80 °C

Final temperature: 40°C

We can calculate the heat released by the water ( $Q_w$ ) when it cools using the following expression.

$Q_w = c \times m \times (T_f - T_i)$

where

c is the specific heat capacity of water (1 cal/g.°C)

$Q_w = \frac{1cal}{g.\°C} \times 300g \times (40\°C - 80\°C) = -1.2 \times 10^{4} cal$

According to the law of conservation of energy, the sum of the heat released by the water ( $Q_w$ ) and the heat absorbed by the reaction ( $Q_r$ ) is zero.

$Q_w + Q_r = 0\\Q_r = -Q_w = 1.2 \times 10^{4} cal$

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3 years ago

29.3g CO2 and 20.8g H2O

docker41 [41]

Answer:

the most best answer is 50.1 you never find such type of answer

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3 years ago