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4 years ago

14

Find the angle of refraction of a ray of light that enters a diamond (n=2.419) from air at an angle of 18.0° to the normal. ONLY

keep 1 decimal in your answer

1 answer:

Tpy6a [65]4 years ago

3 0

Answer:

n

Explanation:

hb

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A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?

Lynna [10]

Answer:

Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

$I=\frac{Q}{t}$

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

I= 19500 A
Q=36 C
t=?

Replacing:

$19500 A=\frac{36 C}{t}$

Solving:

19500 A*t= 36 C

$t=\frac{36 C}{19500 A}$

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)

<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>

8 0

3 years ago

A reaction that releases energy as it occurs is classified as a(n ________.

cluponka [151]

The reaction that releases energy is called an EXOTHERMIC process. This is a word from the prefix exo- which means to exit and from the root word therm which is a unit of heat which in turn is form of energy. This is the opposite process of ENDOTHERMIC process.

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3 years ago

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

sergij07 [2.7K]

Answer:

A) 50.0 g Al

Explanation:

We can calculate the temperature change of each substance by using the equation:

$\Delta T=\frac{Q}{mC_s}$

where

Q = 200.0 J is the heat provided to the substance

m is the mass of the substance

$C_s$ is the specific heat of the substance

Let's apply the formula for each substance:

A) m = 50.0 g, Cs = 0.903 J/g°C

$\Delta T=\frac{200}{(50)(0.903)}=4.4^{\circ}C$

B) m = 50.0 g, Cs = 0.385 J/g°C

$\Delta T=\frac{200}{(50)(0.385)}=10.4^{\circ}C$

C) m = 25.0 g, Cs = 0.79 J/g°C

$\Delta T=\frac{200}{(25)(0.79)}=10.1^{\circ}C$

D) m = 25.0 g, Cs = 0.128 J/g°C

$\Delta T=\frac{200}{(25)(0.128)}=62.5^{\circ}C$

E) m = 25.0 g, Cs = 0.235 J/g°C

$\Delta T=\frac{200}{(25)(0.235)}=34.0^{\circ}C$

As we can see, substance A) (Aluminium) is the one that undergoes the smallest temperature change.

7 0

3 years ago

Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 m apart and are emitting

horsena [70]

Answer:

Explanation:

Wave length of sound from each of the speakers = 340 / 1700 = .2 m = 20 cm

Distance between first speaker and the given point = 4 m.

Distance between second speaker and the given sound

= √ 4² + 2² = √16 +4 = √20 = 4.472 m

Path difference = 4.472 - 4 = .4722 m.

Path difference / wave length = 0.4772 / 0.2 = 2.386

This is a fractional integer which is neither an odd nor an even multiple of half wavelength. Hence this point of neither a perfect constructive nor a perfect destructive interference.

7 0

4 years ago

The fast server in women's tennis is Venus Williams, who recorded a serve of 130 mi/h (209 km/h) in 2007 If her racket pushed on

Darina [25.2K]

209 km/h = 58.0 m/s

2as = v² - u²
Assuming the ball started from rest,

a = (58)² / 2 x 0.11

a = 15,290 m/s²

7 0

3 years ago