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Alex73 [517]
3 years ago
14

Find the angle of refraction of a ray of light that enters a diamond (n=2.419) from air at an angle of 18.0° to the normal. ONLY

keep 1 decimal in your answer
Physics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

n

Explanation:

hb

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In the absence of a gravitational force, the weight of a body is?
azamat

Answer:

0

Explanation:

Weight = mass x gravity

if gravity = 0 then Weight =0 as well

5 0
2 years ago
The info below shows three kettles with their powers and the time they take to boil 500cm3 of water. If electricity costs 9p per
dimaraw [331]

The cost of boiling 500 cm³ of water using the 3 KW Kettle is 1.35p

<h3>What is power? </h3>

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = Energy (E) / time (t)

P = E / t

<h3>How to determine the energy</h3>
  • Power (P) = 3 KW
  • Time (t) = 3 mins = 3 / 60 = 0.05 h
  • Energy (E) =?

E = Pt

E = 3 × 0.05

E = 0.15 KWh

<h3>How to determine the cost</h3>
  • Energy (E) = 0.15 KWh
  • Cost per unit = 9p
  • Cost =?

Cost = Energy × cost per unit

Cost = 0.15 × 9

Cost = 1.35p

Learn more about electrical power:

brainly.com/question/64224

#SPJ1

8 0
1 year ago
Use the vocabulary in the Word Bank to complete the following explanation.
ahrayia [7]
Where’s the vocabulary?
5 0
3 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
2 years ago
When ___ attacks the surface of a metal, it becomes tarnished.​
alexandr1967 [171]

Answer:corrosion (i believe)

Explanation:

6 0
3 years ago
Read 2 more answers
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