Water-rich solutions carrying metallic salts fill cracks and form <u>veins</u>.
Answer:
pH = 4.164
Explanation:
The first process is to find the initial moles for the base (B) & the acid (HA)
i.e.
The acid with base reaction is expressed as;
HA + B → A⁻ + HB⁺
to 1.493 × 10⁻³ 2.047 × 10⁻³ - -
- 1.493 × 10⁻³ 1.493 × 10⁻³ 1.493 × 10⁻³ 1.493 × 10⁻³
0 5.54 × 10⁻⁴ 1.493 × 10⁻³ 1.493 × 10⁻³
From observation; both the acid & base weak
Given that:
The pKa for base = 4.594
The pKa for acid = 3.235
Recall that;
pKa = -log Ka
So; Ka =
By applying this:
For Base; Ka = = 2.5468 × 10⁻⁵
For Acid: Ka = = 5.821 × 10⁻⁴
After the reaction; we have the base with its conjugate acid & conjugate base of acid; Thus, since the conjugate acid of the base possesses a higher value of K, it is likely it would be the one to define the pH of the solution.
By analyzing the system, we have:
HB⁺ + H₂O ↔ B + H₃O⁺
to 0.01493 M 0.00554 M
- x x x
0.01493 - x 0.00554 - x x
Thus;
Using the common ion effect;
0.00554 - x 0.00554 &
0.01493 - x 0.01493
∴
x = [H₃O⁺] = 6.8635 × 10⁻⁵
∴
pH = -log(6.8635 × 10⁻⁵)
pH = 4.164
Answer:
Al(OH)₃ + 3 HCl ----> AlCl₃ + <u>3 H₂O</u>
Explanation:
In a double-displacement reaction, the cation of one compound is swapped with the cation of another. The basic structure of these reactions is:
AB + CD ----> AD + CB
In this reaction, the aluminum (Al) of Al(OH₃) is replaced by the hydrogen (H) of HCl, and vice versa.
The first resulting compound is AlCl₃. The chlorine has a subscript of 3 in order to eliminate the +3 charge from the Al cation (+3 + 3(-1) = 0). The second resulting compound is HOH, most commonly written as H₂O. There needs to be a coefficient of 3 in front of H₂O to balance the equation.
The complete balanced equation is:
Al(OH)₃ + 3 HCl ----> AlCl₃ + <u>3 H₂O</u>
0.1 mol / L * 1L/1000mL = 0.0001 mol / mL
using sigs figs
1×10^-4 mol /mL