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pychu [463]
2 years ago
6

Given: 4Na + O2 → 2Na2O In this chemical reaction, how many moles of Na2O will be produced if 2.90 moles of Na react completely?

Express your answer to three significant figures.
Chemistry
1 answer:
crimeas [40]2 years ago
3 0

Since we already have the balanced equation, we know that the ratio between Na:Na_{2}O is 4:2 respectively.

So then we can set up a proportion to find the number of moles produced when 2.90 moles of Na react completely:

\frac{4mol_{Na}}{2mol_{Na_{2}O}} =\frac{2.90mol_{Na}}{xmol_{Na_{2}O}}

Then we cross multiply and solve for x:

4x=5.8

x=1.45

Therefore, we know that when 2.90 moles of Na react completely, there are 1.45 moles of Na_{2}O that are produced.

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In a reaction involving the iodination of acetone, the following volumes were used to make up the reaction mixture: 5 mL 4.0M ac
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Explanation:

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7 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
PLz help ASAP
Andrews [41]
  1. it is at the bottom trust me i did the test
6 0
2 years ago
Read 2 more answers
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