Answer:
C) The amount of water released through the dam and the dam's height account for the potential energy
Explanation:
The gravitational potential energy of an object is given by:
where
m is the mass of the object
g is the acceleration of gravity
h is the height of the object relative to the ground
As we see from the equation, the potential energy depends on two factors related to the object:
- its mass
- its height above the ground
So for the water in the dam, its potential energy depends on
- the mass of the water (= the amount of water released)
- the height of the water (= the dam's height)
So the correct answer is
C) The amount of water released through the dam and the dam's height account for the potential energy
Answer:
The answer is theory. Hope that's the right answer
<span>To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from the x axis.
</span>
<span>The 110 N force is said to act at 90 deg which means it is along the Y axis. The </span><span>55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the
</span>
<span>X component of the resultant force = 55 N </span>
<span>Y component of the resultant force = 110 N </span>
<span>Magnitude of the resultant force would be calculated as follows:
R = √(Fx^2 + Fy^2)
R = √(55^2 + 110^2) </span>
<span>R = √(15125) </span>
<span>R = 123 N </span>
<span>The resultant force would have its terminal side in the x-axis. We calculate angle θ as follows:
</span>
<span>tan θ = Fy/Fx </span>
<span>tan θ = 110 N /55 N = 2
</span>θ = arctan(2)
θ <span>= 63.4 degrees
</span>Therefore, the m<span>agnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.</span>
Answer:
Following are the responses to the given question:
Explanation:
The mass (mg) is downwards, the typical pressure is upward. This pushing force of is pushed forward by skater 3 on skater 2. (considered as rightward direction). The strength of the slater 2 in reply is the slater Skater three moves to the left.
Its push force imparted to the skateboarder 2 in relation those above forces The force on skater 2 by skater 1 is as a response, to a left. Skater 2's free body system is as follows: