The velocity of the object s calculated as 22.1 m/s.
<h3>What is the speed of the object?</h3>
Given that we can write that;
v^2 = u^2 + 2gh
Now u = 0 m/s because the object was dropped from a height
v^2 = 2gh
v = √2 * 9.8 * 25
v = 22.1 m/s
Learn more about velocity:brainly.com/question/18084516
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Answer:
Explanation:
Volume per unit time flowing will be conserved
a₁v₁ = a₂ v₂
π r₁² x v₁ = π r₂² x v₂
(0.9 x 10⁻²)² x .35 = ( .45 x 10⁻² )² x v₂
v₂ = 1.4 m / s
Answer:
The gravitational force is related to the mass of each object.
The gravitational force is an attractive force.
Explanation:
Gravitational force is a long range force of attraction between any two masses.
Mathematically given as :
![F=G.\frac{m_1.m_2}{r^2}](https://tex.z-dn.net/?f=F%3DG.%5Cfrac%7Bm_1.m_2%7D%7Br%5E2%7D)
where:
are the masses
r= distance between the center of mass of the two objects.
G= gravitational constant = ![6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}](https://tex.z-dn.net/?f=6.67%5Ctimes%2010%5E%7B-11%7D%20m%5E3.kg%5E%7B-1%7D.s%5E%7B-2%7D)
From the above relation of eq. (1) it is clear that,
Gravitational force is inversely proportional to the square of the distance and directly proportional to the masses.
The mass of an object is independent of its size due to the fact that density may vary for different objects.
The force of gravity varies with height as:
![\frac{g}{g_x} =(\frac{r_x}{r} )^2](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7Bg_x%7D%20%3D%28%5Cfrac%7Br_x%7D%7Br%7D%20%29%5E2)
where:
![g=9.8\,m.s^{-2}](https://tex.z-dn.net/?f=g%3D9.8%5C%2Cm.s%5E%7B-2%7D)
gravity at height
of the center of mass of the object from the center of mass of the earth.
and we know that force:
![F=m\times g](https://tex.z-dn.net/?f=F%3Dm%5Ctimes%20g)
where: m= mass of the object.
Answer:
The units (km/h) tell you how to do this! 200km/3h = 66.66666666…. BUT technically you only have ONE significant digit: 3 so 66.666… rounded to ONE digit is 70km/h but that is probably not important in this intro class so V = 66.67 or 67 km/h
Answer:
<h2>3.39 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
![k = \frac{1}{2} m {v}^{2} \\](https://tex.z-dn.net/?f=k%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20m%20%7Bv%7D%5E%7B2%7D%20%20%5C%5C%20)
m is the mass
v is the velocity
From the question we have
![k = \frac{1}{2} \times 1.4 \times {2.2}^{2} \\ = 0.7 \times 4.84 \\ = 3.388 \: \: \: \: \: \: \: \: \:](https://tex.z-dn.net/?f=k%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%201.4%20%5Ctimes%20%20%7B2.2%7D%5E%7B2%7D%20%20%5C%5C%20%20%3D%200.7%20%5Ctimes%204.84%20%5C%5C%20%20%3D%203.388%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
We have the final answer as
<h3>3.39 J</h3>
Hope this helps you