Answer:
The angular velocity is 15.37 rad/s
Solution:
As per the question:
Horizontal distance, x = 30.1 m
Distance of the ball from the rotation axis is its radius, R = 1.15 m
Now,
To calculate the angular velocity:
Linear velocity, v =
v =
v =
v =
Now,
The angular velocity can be calculated as:
Thus
Answer:
d = (75 i ^ + 93 j ^ + 27 k ^) m , d2 = (900 i ^ + 1116 j ^ + 324 k ^) m
Explanation:
The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation
v = d / t
d = v t
Reduce time to units SI
t = 5 min (60 s / 1 min) = 300 s
X axis
x = vₓ t
x = 0.25 300
x = 75 m
Y axis
y = t
y = 0.31 300
y = 93 m
Z axis
z= t
z = 0.09 300
z = 27 m
d = (75 i ^ + 93 j ^ + 27 k ^) m
For the time of 1 h
t2 = 1 h (3600s / 1 h) = 3600
x2 = 900 m
y2 = 1116 m
z2 = 324 m
d2 = (900 i ^ + 1116 j ^ + 324 k ^) m