Question

What is the force between two proton’s that are 0.005m apart?

Answer 1

Answer:

Force, $F=9.21\times 10^{-24}\ N$

Explanation:

Distance between proton is 0.005 m

It is required to find the force between two protons. Protons have of positive charge of $1.6\times 10^{-19}\ C$. Two protons will have a force of repulsion between them. The force is given by :

$F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.005)^2}\\\\F=9.21\times 10^{-24}\ N$

So, the force between two protons is $9.21\times 10^{-24}\ N$.