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steposvetlana [31]
3 years ago
10

If you have an immovable object on a table, and you remove the table from under the object, like in the tablecloth trick what wi

ll happen to the immovable object? Will it fall? Isn't it immovable? Will it just float there? What about gravity?
Physics
1 answer:
Airida [17]3 years ago
4 0

It will not move because you said it is immovable which is immpossible but if it really is unable to move no matter what then it wont move but logicalls if it was real yeah it would move, because of ghravity.

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A stream of warm water is produced in a steady-flow mixing process by combining 1.0 kg/s of cool water at 25 °C with 0.8 kg/s of
Tamiku [17]

Explanation:

The given data is as follows.

      m_{1} = 0.8 kg/s = 800 g,      C_{1} = 4.18 J/g^{o}C

     m_{2} = 1 kg = 1000 g,   T_{1} = (75 - T),

     T_{2} = T - 25

Now, according to the law of conservation of energy,

         m_{1}C_{1}T_{1} = m_{2}C_{2}T_{2} + mL

     800 \times 4.18 \times (75 - T) = 1000 \times 4.18 \times (T - 25) + 30000

      250.8 - 3.34T = 4.18T - 104.5 + 30

          T = \frac{325.3}{7.52}

              = 43.23^{o}C

Thus, we can conclude that temperature of the warm water stream is 43.23^{o}C.

4 0
3 years ago
Only Women and children can be victims of domestic violence
aleksandrvk [35]
That statement is wrong.

Domestic violence could happen to anyone.

There are a lot of cases in which the domestic violence's victims are men or elderly people.
5 0
3 years ago
Read 2 more answers
Suppose the number of coils in the solenoid of an electromagnet is increased. What happens to the electromagnet?
Akimi4 [234]

Answer:

Its strength becomes greater.

Explanation:

5 0
2 years ago
Read 2 more answers
Starting from rest, a 2.3x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts
Harman [31]

Answer:

3.13 m/s

Explanation:

From the question,

Since the flea spring started from rest,

Ek = W................... Equation 1

Where Ek = Kinetic Energy of the flea spring, W = work done on the flea spring.

But,

Ek = 1/2mv²............ Equation 2

Where m = mass of the flea spring, v = flea's speed when it leaves the ground.

substitute equation 2 into equation 1

1/2mv² = W.................... Equation 3

make v the subject of the equation

v = √(2W/m)................. Equation 4

Given: W = 3.6×10⁻⁴ J, m = 2.3×10⁻⁴ kg

Substitute into equation 4

v = √[2×3.6×10⁻⁴ )/2.3×10⁻⁴]

v = 7.2/2.3

v = 3.13 m/s

Hence the flea's speed when it leaves the ground  = 3.13 m/s

4 0
3 years ago
If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
3 years ago
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