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Firdavs [7]
3 years ago
10

Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 79.9 N , Jill pul

ls with 73.3 N in a direction 45° to the left, and Jane pulls in a direction 45° to the right with 137 N . (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) Find the magnitude of the net force the people exert on the donkey.
Physics
1 answer:
Lena [83]3 years ago
8 0

Answer:

Explanation:

Please refer the following link for your answer

https://www.assignmentexpert.com/homework-answers/physics-answer-73840.pdf

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In the picture of a planet in orbit around its star area a is double that of area b. What is true of the time the planet takes t
aalyn [17]
The Kepler's laws predict the planetary motion, so there are three laws for this, namely:

1. The orbit of a planet is an ellipse with the Sun (the sun is a star!) at one of the two focus.

2. A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.

3. The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.

So, let's use second law. The Sun sweeps out equal areas during equal intervals of time means that if A = B, the time the planet takes to travel A1A2 is equal to the time the planet takes to travel B1B2, but given that A = 2B, then takes twice the time to travel A1A2 compared to B1B2.
8 0
3 years ago
A car starts from rest and goes down a slope with a constant
GREYUIT [131]

Answer:

25m/s

Explanation:

here we use 1st equation of motion

then we find this ans

3 0
3 years ago
Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector
Sav [38]
Good morning.

We see that \mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}

The magnitude(norm, to be precise) can be calculated the following way:

\star \ \boxed{\mathsf{\overset{\to}{a}=(x, y,z)\Rightarrow ||\overset{\to}{a}|| = \sqrt{x^2+y^2+z^2}}}


Now the calculus is trivial:

\mathsf{\|\overset{\to}{b} \| =\sqrt{4^2+4^2+2^2} =\sqrt{16+16+4}}\\ \\ \mathsf{\|\overset{\to}{b}\|=\sqrt{36}}\\ \\ \boxed{\mathsf{\|\overset{\to}{b}\| = 6.00 \ u}}
7 0
3 years ago
A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular
Fynjy0 [20]

Answer:

Bank angle = 35.34o

Explanation:

Since the road is frictionless,

Tan (bank angle) = V^2/r*g

Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2

Tan ( bank angle) = 40^2/(230*9.81)

Tan (bank angle) = 0.7091

Bank angle = tan inverse (0.7091)

Bank angle = 35.34o

3 0
3 years ago
It is found that a 5.70 m segment of a long string contains three complete waves and has a mass of 180 g. The string is vibratin
Hoochie [10]

Answer:

1.9 m.

Explanation:

Three complete waves in the length of 5.7 m

The distance traveled by one complete wave is called wavelength.

Thus, the distance traveled by one wave = 5.7 / 3 = 1.9 m

Thus, the wavelength is 1.9 m.

3 0
3 years ago
Read 2 more answers
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