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Leviafan [203]
3 years ago
12

1s22s22p63s23p64s23d104p6. This ion is a(n) . What is the chemical symbol of the noble gas this ion is isoelectronic with?

Chemistry
2 answers:
leonid [27]3 years ago
3 0

1) Answer is: This ion is Br⁻ (bromine anion).

This ion has 36 electrons, because it has charge -1 (atom gain one electron), its atom has 35 electrons and 35 protons (atomic number 35). Element with atomic number 35 is bromine.

Electron configuration of ion with a charge of -1:                                                    ₃₅Br⁻ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶.

2) Answer is: chemical symbol of the noble gas is Kr (krypton).

Isoelectronic atom or ion has the same number of valence electrons. Krypton has 36 electron and 36 protons (atomic number 36).

Andrej [43]3 years ago
3 0

Isoelectronic species are species with same number of electrons.

The given electronic configuration of the ion is as follows:

1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}

Check for the total number of electrons in the ion. The sum of number of electrons in all shells according to given electronic configuration is 36. Number of electrons in a neutral atom is equal its atomic number. According to periodic table, atomic number of krypton is 36, which is a noble gas and belongs to 18th group with electronic symbol Kr. It has the same electronic configuration thus, it is isoelectronic with the ion.

Therefore, the chemical symbol for noble gas isoelectronic with the given ion is Kr.

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Antoine Lavoisier burned metals in sealed jars. What is your prediction of his experimental results?
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The mass of the jar and contents remained the same after the metal was burned.

Explanation:

My prediction about the experimental results is that  the mass of the jar and contents remained the same after the metal was burned in the jar.

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During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2
ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass  of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol =<u> 12.81 grams</u>

Step 6:  Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = <u>75.70 grams CO2</u>

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = <u>34.29 grams</u>

3 0
4 years ago
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