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2 years ago

Which of the following describes how the moons of Jupiter are similar to Earth?

1 answer:

5 0

"Jupiter's moons orbit Jupiter much like the Earth orbits the Sun" describes how the moons of Jupiter are similar to Earth.

<u>Explanation:</u>

In the solar system, Jupiter, the one considered as the largest planet, whose earth's mass seems to be more than 300 times, it is also the most massive. Its diameter plays a major role in the percentage of moons encircling Jupiter since it has a wide area of gravitational strength to support several moons around it.

The orbital periods which range from seven hours to roughly three Earth years in Jupiter's moons. A few of the orbits are almost circular, whereas the moons farthest from Jupiter are more uneven.

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How did settlers changed the great plains?

Paul [167]

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3 years ago

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Goryan [66]

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Explanation:

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3 years ago

In a circuit of two lamps in parallel there is 5 v across one lamp. what is the voltage across the other lamp? answer in units o

natima [27]

The voltage across the other lamp is also 5 V.
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3 years ago

Charlie drove around the block at constant velocity, is it true or false?

Paha777 [63]

Answer:

FALSE I THINK

Explanation:

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3 years ago

iris [78.8K]

Answer:

t = 1.659s

Explanation:

We can use the kinematics equations to solve this questions:

v = u + at

$v^{2} = u^{2} +2as$

where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement

a) Given information from the question,

u = $\frac{70km}{h} =\frac{(70*1000)m}{(1*3600)s} = 19.444m/s$ (Convert km/h to m/s first)

a = $2m/s^{2}$

s = 35m

Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.

$v^{2} =(19.444)^{2} +2(2)(35)\\v=\sqrt{(19.444)^{2} +2(2)(35)} \\v= 22.761m/s (5.sf)\\$

b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.

v = u + at

22.761 = 19.444 + 2t

2t = 22.761 - 19.444

t = $\frac{22.761-19.444}{2}$

t = 1.659s

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2 years ago