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JulsSmile [24]
4 years ago
14

NaI+pb(so4)2=Pbi4+Na2(so4) How do you balance this equation

Chemistry
1 answer:
Ipatiy [6.2K]4 years ago
6 0

Answer:

By putting a coefficient 4 on NaI and 2 on Na₂SO₄

4NaI + Pb(SO₄)₂ → Pbi4 + 2Na₂SO₄

Explanation:

  • A chemical equation is balanced for it to obey the law of conservation of mass.
  • According to the law of conservation of mass, the mass of the reactants should be equal to the mass of products.
  • Balancing involves putting coefficients on reactants and products to get an equal number of atoms of each element on either side of the equation.
  • In this case, putting a coefficient four on NaI and two on Na₂SO₄ will make the equation to be balanced.
  • Therefore, the balanced chemical equation is;

4NaI + Pb(SO₄)₂ → Pbi4 + 2Na₂SO₄

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How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg
Afina-wow [57]

Answer : The mass of PbSO_4 needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4 produced from 1 mole of PbSO_4

So, 0.005 mole of PbCrO_4 produced from 0.005 mole of PbSO_4

Now we have to calculate the mass of PbSO_4

\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

Therefore, the mass of PbSO_4 needed are, 1.515 grams.

6 0
3 years ago
What general trend applies to solubility?
Marysya12 [62]

Answer:

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