Answer:
no
Step-by-step explanation:
no no no no no no no no no no nø no no

As we know ~
Area of the circle is :

And radius (r) = diameter (d) ÷ 2
[ radius of the circle = half the measure of diameter ]
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<h3>Problem 1</h3>



Now find the Area ~




・ .━━━━━━━†━━━━━━━━━.・
<h3>problem 2</h3>



Bow, calculate the Area ~




・ .━━━━━━━†━━━━━━━━━.・
<h3>Problem 3 </h3>




・ .━━━━━━━†━━━━━━━━━.・
<h3>Problem 4</h3>



now, let's calculate area ~



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<h3>problem 5</h3>



Now, let's calculate area ~




・ .━━━━━━━†━━━━━━━━━.・
<h3>problem 6</h3>




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The number is less than 190,000 and greater than 180,000
5,000 more than the number has 187 thousands
2000 less than the number has 4 hundreds
180, 000 <n> 190, 000
180,000 + 2000 = n = 5000-187, 000
182,000 = n = 182, 000
Or,
180, 000 <n> 190,000
n + 5000= 187, 000 n – 2000 = 180, 000
n= 187, 000- 5000 n = 180, 000 + 2000
n= 182, 000 n= 182, 000
The answer is A because 24 3/8 inches is roughly 2 feet, 100/2 is 50, and since there is a small 3/8 value, the answer is 49
Answer:
17 million
Step-by-step explanation:
-0.34(
) + 4.43(8) + 3.46
-21.76 + 35.44 + 3.46
13.68 + 3.46
17.14
Answer: C 17 million
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