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Leviafan [203]
3 years ago
5

True or false. a wheel and axle are a rotating lever that move around an effort arm?

Chemistry
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

True

Explanation:

the machine shown in figure 9.9 is called a wheele and axle. It's a form of lever. the effort arm can rotate in a complete circle, which is the center of the axle.

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When 18.5 g of HgO(s) is decomposed to form Hg(l) and O2(g), 7.75 kJ of heat is absorbed at standard-state conditions. What is t
taurus [48]

Answer:

The standard enthalpy of formation of HgO is -90.7 kJ/mol.

Explanation:

The reaction between Hg and oxygen is as follows.

\text{Hg(l)}+\frac{1}{2}{O_{2}\rightarrow \text{HgO(s)}

From the given,

Molar mass of HgO = 216.59 g/mol

Mass of HgO decomposed = 18.5 g

Amount of heat absorbed = 7.75 kJ

From the reaction,

The standard  enthalpy of formation = +7.75\times\frac{kJ}{18.5 g}\frac{216.59}{1mol} \,\,= +90.7 kJ/mol

During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.

For the formation of 1 mol of HgO , 90.7 kJ of energy is release

Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol

5 0
3 years ago
What has to happen to join two monosaccharide units into a disaccharide?
omeli [17]
A condensation reaction forming a glycosidic bond. so in other words a monosaccharide joining together to form a disaccharide. 

5 0
3 years ago
Based on the Valence Shell Electron Pair Repulsion Theory (or VSEPR), molecules will arrange to keep the following as far apart
elena55 [62]

Answer:

B. Valence Electron Pairs

Explanation:

Valence-shell electron-pair repulsion, or VSEPR, describes the shape of molecules by determining the repulsion of valence electrons. Therefore, our answer is B.

6 0
3 years ago
Commercial concentrated aqueous ammonia is 28% nh3 by mass and has a density of 0.90 g/ml. what is the concentration of ammonia
patriot [66]

Answer:- 14.9 M

Solution:- Given commercial sample of ammonia is 28% by mass. Let's say we have 100 grams of the sample. Then mass of ammonia would be 28 grams.

Density of the solution is given as 0.90 grams per mL.

From the mass and density we could calculate the volume of the solution as:

100g(\frac{1mL}{0.90g})

= 111 mL

Let's convert the volume from mL to L as molarity is moles of solute per liter of solution.

111mL(\frac{1L}{1000mL})  

= 0.111 L

Now, we convert grams of ammonia to moles on dividing the grams by molar mass. Molar mass of ammonia is 17 gram per mole.

28g(\frac{1mole}{17g})

= 1.65 mole

To calculate the molarity we divide the moles of ammonia by the liters of solution:

molarity=\frac{1.65mole}{0.111L}

= 14.9 M

So, the molarity of the given commercial sample of ammonia is 14.9 M.

5 0
3 years ago
As much sugar as will dissolve is added to hot water. The water is then
Katen [24]
The answer is C because it says describe the final sugar and C is unsaturated and in the problem it says as much as sugar will dissovle .
8 0
3 years ago
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