Question

How many moles of ammonium carbonate are needed to decompose in order to produce 6.52g of carbon dioxide? Ammonium oxide is the other product.
A.) 0.116 moles

B.) 0.251 moles

C.) 0.148 moles

D.) 286.88 moles


Help me solve please...

Answer 1

Answer:

Option (C) is correct.

Explanation:

Decomposition reaction: $(NH_{4})_{2}CO_{3}\rightarrow 2NH_{3}+CO_{2}+H_{2}O$

Molar mass of $CO_{2}$ = 44.01 g/mol

No. of moles = (mass)/(molar mass)

So, 6.52 g of $CO_{2}$ = $\frac{6.52}{44.01}$ moles of $CO_{2}$ = 0.148 moles of $CO_{2}$

According to balanced equation-

1 mol of $CO_{2}$ is produced from decomposition of 1 mol of $(NH_{4})_{2}CO_{3}$

So, 0.148 mol of $CO_{2}$ is produced from decomposition of 0.148 mol of $(NH_{4})_{2}CO_{3}$

Hence, option (C) is correct.