Answer:
pKb = 10.96
Explanation:
Tartaric acid is a dyprotic acid. It reacts to water like this:
H₂Tart  +  H₂O  ⇄  H₃O⁺   +  HTart⁻         Ka1
HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2
When we anaylse the base, we have
Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1
HTart⁻  +  H₂O  ⇄  OH⁻  +    H₂Tart          Kb2
Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14
Kb2 = Kw / Ka1  →   1×10⁻¹⁴ / 9.20×10⁻⁴  = 1.08×10⁻¹¹
so pKb = - log Kb2   → - log 1.08×10⁻¹¹ = 10.96  
 
        
                    
             
        
        
        
It will probably turned into a gumy
        
                    
             
        
        
        
The answer is A),<span>carbon,hydrogen,and oxygen
Hope this helps
</span>
        
                    
             
        
        
        
The chemical equation given is:
<span>2x(g) ⇄ y(g)+z(s)</span>
Answer: the higher the amount of x(g) the more the forward reacton will occur and the higher the amounts of  products y(g) and z(s) will be obtained at equilibrium.
Justification:
As Le Chatellier's priciple states, any change in a system in equilibrium will be compensated to restablish the equilibrium.
The higher the amount, and so the concentration, of X(g), the more the forward reaction will proceed to deal witht he high concentration of X(g), leading to an increase on the concentration of the products y(g) and z (s). 
        
             
        
        
        
I believe this topic is quantitative chemistry but I need the equation to work this out sorry