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Eva8 [605]
3 years ago
11

You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finis

hed grilling, the temperature is 95°F and the propane tank reads 74 psi. Come nighttime the outside temperature drastically decreases to 20°C. What is the pressure of the propane tank at night?
Select one:

a. 16 kPa

b. 485 kPa

c. 107 kPa

d. 2300 kPa
Chemistry
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

b. 485 kPa

Explanation:

Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:

P1T2 = P2T1

<em>P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas</em>

<em>Where P1 = 74psi</em>

<em>T2 = 20°C + 273.15 = 293.15K</em>

<em>P2 = ?</em>

<em>T1 = (95°F -32) * 5/9 + 273.15 = 308.15K</em>

<em />

Replacing:

74psi*293.15K = P2*308.15K

70.4psi

In kPa:

70.4psi * (6.895kPa / 1psi) =

<h3>b. 485 kPa </h3>

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3 years ago
How do you balance the equation in number one?
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To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

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Concentration of unknown acid is 0.061 M

Given:

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Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

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Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

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0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

Learn more about Concentration here:

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