The average propane cylinder for a residential grill holds approximately 18 kg of propane. How much energy (in kJ) is released b
1 answer:
Combustion is a chemical reaction between a fuel and an oxidant, oxygen, to give off combustion products and heat. Complete combustion results when all of the fuel is consumed to form carbon dioxide and water, as in the case of a hydrocarbon fuel. Incomplete combustion results when insufficient oxygen reacts with the fuel, forming soot and carbon monoxide.
The complete combustion of propane proceeds through the following reaction:
+ 
--> 
+ 
Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic.
The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.
14.50 kg propane x <u> 1000 g </u> x <u> 1 mole propane </u> x <u> 2220 kJ </u>
1 kg 44.1 g 1 mole
= 729,931.97 kJ
The complete combustion of propane proceeds through the following reaction:
Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic.
The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.
14.50 kg propane x <u> 1000 g </u> x <u> 1 mole propane </u> x <u> 2220 kJ </u>
1 kg 44.1 g 1 mole
= 729,931.97 kJ
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The answer for the following problem is mentioned below.
- <u><em>Therefore the final volume of the gas is 100 ml.</em></u>
Explanation:
Given:
Initial pressure () = 600 mm of Hg
Final pressure () = 1200 mm of Hg
Initial volume () = 200 ml
To find:
Final volume ()
We know;
According to the ideal gas equation,
P × V = n × R × T
Where;
P represents the pressure of the gas
V represents the volume of the gas
n represents the no of moles of the gas
R represents the universal gas constant
T represents the temperature of the gas
So,
From the above mentioned equation,
P × V = constant
=
Where,
() represents the initial pressure of the gas
() represents the final pressure of the gas
() represents the initial volume of the gas
() represents the final volume of the gas
So;
=
= 100 ml
<u><em>Therefore the final volume of the gas is 100 ml.</em></u>
Answer: 1.
2. 3 moles of : 2 moles of
3. 0.33 moles of : 0.92 moles of
4. is the limiting reagent and
is the excess reagent.
5. Theoretical yield of is 29.3 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
3 moles of require = 2 moles of
Thus 0.33 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 3 moles of give = 2 moles of
Thus 0.33 moles of give =
of
Theoretical yield of
Thus 29.3 g of aluminium chloride is formed.