Answer:
3400 m
Explanation:
Both lightning and thunder happen at the same time but one is faster than the other. The distance traveled by a sound can be calculated from its speed such that;
speed = distance/time, hence, distance = speed x time.
<em>For a thunder with 340 m/s speed and 10 seconds away from lightning, the distance between the thunder and the lightning can be calculated as</em>;
distance = 340 m/s x 10 s = 3400 m
Answer:
a) Acceleration is zero
, c) Speed is cero
Explanation:
a) the equation that governs the simple harmonic motion is
x = A cos (wt +φφ)
Where A is the amplitude of the movement, w is the angular velocity and φ the initial phase determined by the initial condition
Body acceleration is
a = d²x / dt²
Let's look for the derivatives
dx / dt = - A w sin (wt + φ)
a = d²x / dt² = - A w² cos (wt + φ)
In the instant when it is not stretched x = 0
As the spring is released at maximum elongation, φ = 0
0 = A cos wt
Cos wt = 0 wt = π / 2
Acceleration is valid for this angle
a = -A w² cos π/2 = 0
Acceleration is zero
b)
c) When the spring is compressed x = A
Speed is
v = dx / dt
v = - A w sin wt
We look for time
A = A cos wt
cos wt = 1 wt = 0, π
For this time the speedy vouchers
v = -A w sin 0 = 0
Speed is cero
Answer:
6926.4J
Explanation:
Given parameters:
Mass of iron = 200g
Initial temperature = 100°C
Final temperature = 22°C
Unknown:
Amount of heat transferred to the water = ?
Solution:
The quantity of heat transferred to the water is a function of mass and temperature of the iron;
H = m c Ф
m is the mass of the iron
Ф is the change in temperature
C is the specific heat capacity of iron = 0.444 J/g°C
Now;
insert the parameters and solve;
H = 200 x 0.444 x (100-22)
H = 6926.4J
Answer:
The recording that Eli and Clara's Seismograph would show will be very close to that a real Seismograph would show. This is because the mechanism they have constructed is very similar to the real one.
Explanation:
hope this helps
