All categories

4 years ago

LIULIS. What would happen to speed if distance increased in the same amount of time?

Physics

1 answer:

Diano4ka-milaya [45]4 years ago

6 0

Answer:

The speed will be increased.

Explanation:

We can better understand this analysis, if we use numerical values and remember the expression or formula for speed. We know that speed is defined as the distance travelled at a given time.

$v=\frac{x}{t} \\where:\\v = velocity [m/s]\\x = distance [m]\\t = time [s]\\$

So if we have the distance x = 4 [m] and the time 2 [s], the speed will be:

v = (4/2) = 2 [m/s]

And if we increase the distance to x = 10 [m] at the same time 2[s], the speed will be:

v = (10/2) = 5 [m/s]

So we can see that the speed is increased.

You might be interested in

Dante is leading a parade across the main street in front of city hall. Starting at city hall, he marches the parade 4 blocks ea

Yuliya22 [10]

Answer:

The displacement is 6.71 [m} and the angle is 63.4° to the north of east

Explanation:

Using a sketch showing Dante's displacement, we can find each of the points Dante moves through. First, it moves 4 blocks east, the new coordinate (4.0), then moves 3 blocks south and we will get the new coordinate (4, -3). Then Dante moves 1 block west, thus the new point is (3, -3). And finally it moves 9 blocks north where the new coordinate in and gets -3 - (-9) = + 6.

The displacement can be found using the equation for the straight line.

$d= \sqrt{(x_{1}-x_{0} )^{2} +(y_{1}-y_{0} )^{2} } \\d= \sqrt{(3-0 )^{2} +(6-0 )^{2} } \\\\d=6.71 [m]\\$

We can realize that the triangle formed is a right triangle, therefore we can find the angle of the displacement.

$tan(a)=\frac{6}{3} \\a=tan^-1(2)\\a=63.4[deg]$

8 0

3 years ago

If an antelope can run 14.1 km in 39 min, how fast is it km/h(for reference , 110 km/h is 65 mph )

shtirl [24]

It might make more sense putting it another way but this is basically it. you just take the minutes and divide them by 60 to convert them to hours. then simplify the ratio

8 0

3 years ago

Read 2 more answers

Light rays in a material with index of refrection 1.29 1.29 can undergo total internal reflection when they strike the interface

deff fn [24]

Answer:

The second material's index of refraction is 1.17.

Explanation:

Given that,

Refractive index of the material, n = 1.29

Critical angle is 65.9 degrees.

We need to find the second material's index of refraction. We know that at critical angle of incidence, angle of refraction is equal to 90 degrees. Using Snell's law as:

$n_1\sin \theta_c=n_2\sin (90)\\\\n_2=n_1\sin \theta_c\\\\n_2=1.29\times \sin (65.9)\\\\n_2=1.17$

So, the second material's index of refraction is 1.17.

7 0

3 years ago

It is illegal for all drivers to use a handheld wireless communication device _____________ unless the vehicle is stopped.

irga5000 [103]

Answer:

A. on any Texas freeway

8 0

3 years ago

Ron weighs a bottle with a mass of 0.5 kilograms on a spring scale. The spring stretches by 1 centimeter. He then weighs a secon

Yuri [45]

Answer:

1 kg

Explanation:

Applying,

Hook's law,

F = ke................. Equation 1

Where F = force, k = force constant of the spring, e = extension.

But from the question,

The weight of the bottle is the force acting on the spring scale

therefore,

mg = ke............ Equation 2

Where m = mass of the bottle, g = acceleration due to gravity.

make k the subject of the equation

k = mg/e............ Equation 3

Given: m = 0.5 kg, e = 1 cm = 0.01 m

Constant: g = 9.8 m/s²

k = (0.5×9.8)/0.01

k = 490 N/m

If the mass of the second bottle is weighed,

given: e = 2 cm = 0.02 m

subtitute into equation 1

m×9.8 = 490×0.02

9.8m = 9.8

m = 9.8/9.8

m = 1 kg.

Hence the mass of the second bottle is 1 kg

5 0

3 years ago