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Norma-Jean [14]
3 years ago
14

LIULIS. What would happen to speed if distance increased in the same amount of time?

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

The speed will be increased.

Explanation:

We can better understand this analysis, if we use numerical values and remember the expression or formula for speed. We know that speed is defined as the distance travelled at a given time.

v=\frac{x}{t} \\where:\\v = velocity [m/s]\\x = distance [m]\\t = time [s]\\

So if we have the distance x = 4 [m] and the time 2 [s], the speed will be:

v = (4/2) = 2 [m/s]

And if we increase the distance to x = 10 [m] at the same time 2[s], the speed will be:

v = (10/2) = 5 [m/s]

So we can see that the speed is increased.

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What single property was the most important in Jesseca’s material?
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Answer:

Jesseca wanted to create a material that reflected most of the light that fell on it.

Explanation:

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2 years ago
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An energy storage system based on a flywheel (a rotating disk) can store a maximum of 3.7 MJ when the flywheel is rotating at 16
Likurg_2 [28]

The moment of inertia of the flywheel is 2.63 kg-m^{2}

It is given that,

The maximum energy stored on the flywheel is given as

E=3.7MJ= 3.7×10^{6} J

Angular velocity of the flywheel is 16000\frac{rev}{min} = 1675.51\frac{rad}{sec}

So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E = \frac{1}{2}Iw^{2}

By rearranging the equation:

I = \frac{2E}{w_{2} }

I = 2.63 kg-m^{2}

Thus the moment of inertia of the flywheel is 2.63 kg-m^{2}.

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7 0
1 year ago
A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60 to a uniform electric fi
Harman [31]

Answer:

a. 1.75 Nm²/C

b. Yes.

Explanation:

a. Electric Flux is given as:

Φ = E*A*cosθ

Where E = electric flux

A = Surface area

Φ = 14 * 0.25 * cos60

Φ = 1.75 Nm²/C

b. Yes, the shape of the sheet will affect the Flux through it. This is because flux is dependent on area of the surface and the area is dependent on the shape of the surface.

4 0
3 years ago
A spring is hung from the ceiling. A 2.0-kg mass suspended hung from the spring extends it by 6.0 cm. A downward external force
Stolb23 [73]

The work done by force on a spring hung from the ceiling will be 1.67 J

Any two things with mass are drawn together by the gravitational pull. We refer to the gravitational force as attractive because it consistently seeks to draw masses together rather than pushing them apart.

Given that a spring is hung from the ceiling with a 2.0-kg mass suspended hung from the spring extends it by 6.0 cm and a downward external force applied to the mass extends the spring an additional 10 cm.

We need to find the work done by the force

Given mass is of 2 kg

So let,

F = 2 kg

x = 0.1 m

Stiffness of spring = k = F/x

k = 20/0.006 = 333 n/m

Now the formula to find the work done by force will be as follow:

Workdone = W = 0.5kx²

W = 0.5 x 333 x 0.1²

W = 1.67 J

Hence the work done by force on a spring hung from the ceiling will be 1.67 J

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8 0
1 year ago
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