1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Norma-Jean [14]
3 years ago
14

LIULIS. What would happen to speed if distance increased in the same amount of time?

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

The speed will be increased.

Explanation:

We can better understand this analysis, if we use numerical values and remember the expression or formula for speed. We know that speed is defined as the distance travelled at a given time.

v=\frac{x}{t} \\where:\\v = velocity [m/s]\\x = distance [m]\\t = time [s]\\

So if we have the distance x = 4 [m] and the time 2 [s], the speed will be:

v = (4/2) = 2 [m/s]

And if we increase the distance to x = 10 [m] at the same time 2[s], the speed will be:

v = (10/2) = 5 [m/s]

So we can see that the speed is increased.

You might be interested in
A fire is burning in a fireplace. Where is the radiation?
mrs_skeptik [129]
I think it’s A.
........
5 0
3 years ago
Many biological systems are well-described by the laws of statistical physics. A simple yet often powerful approach is to think
GuDViN [60]

Answer:

z1/z2

Explanation:

we have no quantum effects therefore we can make use of Maxwell Boltzmann distribution in the description of this system.

using the boltzman distribution the probability of finding a particle in energy state

P_{ei}  = \frac{gie^{-ei/kol} }{z}

we have

gi to be degeneration of the ith state

ei to be energy of ith state

z=e^{-ei/kbt} summation

P_{ope} = \frac{e^{-ei/kBt} }{z} = \frac{Z_{1} }{Z}

We have R to be equal to

\frac{P_{ope} }{P_{Close} } = \frac{Z1}{Z2}

8 0
3 years ago
10 POINTS!! SPACE QUESTION!!
wlad13 [49]
The First one trust...
5 0
3 years ago
Read 2 more answers
A solid cube of side 5cm has a mass of 250g. What is its density in kgm ??​
Mariulka [41]

Answer:

5kgm

Explanation:

convert cm to m and g to kg

250/1000=0.25kg

5/1000=0.05m

then find the density

density=mass/volume

=0.25kg/0.05m

=5kgm

7 0
2 years ago
A neutral copper block is polarized as shown in the figure below, due to an electric field made by external charges (notshown).
Fudgin [204]

Answer:

As point B is located inside the copper block so net electric field at point B is j.

Explanation:

Consider the figure attached below. The net electric field at location B,that is inside the copper block is zero because when a conductor is charged or placed in an electric field of  external charges, net charge lies on the surface of conductor and there is no electric field inside the conductor. As point B is located inside the copper block so net electric field at point B is zero as well direction of net electric field at point B is zero.

6 0
3 years ago
Other questions:
  • An 8 kg mass moving at 8 m/s collides with a 6 kg mass
    15·1 answer
  • What is a situation when you might travel at a high velocity, but with low acceleration?
    5·2 answers
  • If I am given a total capacitence of two capacitors, their capacitence togather is 22 F. What capacitence would the individual c
    8·1 answer
  • How does a free-body diagram tell you about the net force on an object?
    8·2 answers
  • Let's see about this one.
    9·2 answers
  • A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder?
    13·1 answer
  • 4. Compare how thermal and electrical energy transfer between objects and give an example of how you can
    6·1 answer
  • A dish is given to you, which contains a blackish-yellow powder. When you move a magnet over it, you are amazed to see black par
    13·1 answer
  • Select the correct answer.
    13·1 answer
  • The resultant of two vectors is of magnitude 3 units and 4 units is 1 units, what is the value of their dot product? ​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!