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Nikolay [14]
3 years ago
15

If you were to walk toward a Van der Graaff generator, the effect of its electrical field would get weaker as you walked towards

it.
True or False
Physics
1 answer:
gavmur [86]3 years ago
7 0

This is False.  

If you walk towards a Vander Graaff generator and touch it, your body will be electrically charged with the same sign as the generator (that’s why your hair stands up, because it is charged with static electricity, and…electrical charges of the same sign repel each other)

Note that the Vander Graaff generator is isolated from the ground, so, if the electrical charge is increased, electrical arcs will form and fly off it to any nearby grounded object or person.


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An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4N/C . How much
cupoosta [38]

Answer:

time will elapse before it return to  its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × 10^{7} m/s

uniform electric field E = 1.18 × 10^{4} N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

so

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

so

put here all value

9.11 × 10^{-31} kg ×a = 1.18 × 10^{4} × 1.602 × 10^{-19}

a = 20.75 × 10^{14} m/s²

so acceleration is 20.75 × 10^{14} m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × 10^{7} = 0 + 20.75 × 10^{14} (t)

t = 11.80 × 10^{-9} s

so time will elapse before it return to  its staring point is

time = 2t

time = 2 ×11.80 × 10^{-9}

time is 23.6 × 10^{-9} s

time will elapse before it return to  its staring point is 23.6 ns

7 0
3 years ago
A place where things are baked <br>​
slava [35]
“A place where things are baked”

- the bakery?
4 0
3 years ago
FAST PLEASE What is the change in internal energy if 90 J of thermal energy is added to a
vladimir1956 [14]
A is right because I took the test
5 0
2 years ago
A nonconducting container filled with 25 kg of water at 23°C is fitted with a stirrer, which is made to turn by gravity acting o
Paul [167]

Explanation:

Given that,

Weight of water = 25 kg

Temperature = 23°C

Weight of mass = 32 kg

Distance = 5 m

(a). We need to calculate the amount of work done on the water

Using formula of work done

W=mgh

W=32\times9.8\times5

W=1568\ J

The amount of work done on the water is 1568 J.

(b). We need to calculate the internal-energy change of the water

Using formula of internal energy

The change in internal energy of the water equal to the amount of the  work done on the water.

\Delta U=W

\Delta U=1568\ J

The  change in internal energy is 1568 J.

(c). We need to calculate the final temperature of the water

Using formula of the change internal energy

\Delta U=mc_{p}\Delta T

\Delta U=mc_{p}(T_{2}-T_{1})

T_{2}=T_{1}+\dfrac{\Delta U}{mc_{p}}

T_{2}=23+\dfrac{1568}{25\times4.18\times10^{3}}

T_{2}=23.01^{\circ}\ C

The final temperature of the water is 23.01°C.

(d). The amount of heat removed from the water to return it to it initial temperature is the change in internal energy.

The amount of heat is 1568 J.

Hence, This is the required solution.

6 0
3 years ago
Technician A says that the HVAC doors in an automatic system are vacuum-operated. Technician B says that the HVAC doors in an au
Gala2k [10]

Option C

Both technicians are correct

<h3><u>Explanation:</u></h3>

HVAC persists for Heating Ventilation and Air Conditioning. Its design in a vehicle is to cleanse, cool, flame, control, and dehumidify the air accessing the cabin, depending on the inputs of the operator as thoroughly as electronic sensors. Various systems will practice diverse ways of regulating airflow into the cabin but all act on identical basic principles.

The automatic systems are electric systems that want different inputs from sensors that intimate climate circumstances to obtain the aspired temperature. Vacuum actuators and/or electric motors control the air doors/valves in these systems.

7 0
3 years ago
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