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3 years ago

Which of the following equations are the correct answer?

Mathematics

2 answers:

alekssr [168]3 years ago

7 0

The answer choices are in the point slope form.

So using the two points on the line we can determine the slope and write the two equations.

Slope = (4 - (-8))/(-2 - (-4))
Slope = 12/2
Slope = 6

Now we know the slope we can use that to write the two equations.

The two equations will be:

y - 4 = 6 (x + 2)
y + 8 = 6 (x + 4)

B and E are the answers.

Hope this helps :)

valentina_108 [34]3 years ago

5 0

(-2,4) and (-4, - 8)
slope = (4 + 8)/(-2+4) = 12/2 = 6

answers are E and B

y - 4 = 6(x + 2)

y + 8 = 6(x + 4)

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What is the length, width, and area

Temka [501]

Length: 6 Width: 2 Area: 12

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3 years ago

Brainliest to the correct answer, but answer ASAP

Lyrx [107]

Answer:

B) 25 / 8

Step-by-step explanation:

We know that pi = 3.14*, or "3 and a little bit more". 25/8=3.125 which is approximately pi.

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2 years ago

WHY IS THIS GETTING DELETED?? I NEED HELP

aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

$\dfrac{(5\times5)^k}{5^{-8}} = 5^3$

$\dfrac{5\times 5^k}{5^{-8}} = 5^3$

If the first one is what you intended, then

$\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3$

and it follows that

2k + 8 = 3 ==> 2k = -5 ==> k = -5/2

If you meant the second one, then

$\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3$

which would give

k + 9 = 3 ==> k = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0

3 years ago

Find the total surface area of this cone. Round to the nearest tenth.

leva [86]

Step-by-step explanation:

for given cone:

h = 3 ft, r = 3 ft

Let l be the Slant height of cone.

$\therefore \: l = \sqrt{ {h}^{2} + {r}^{2} } \\ = \sqrt{ {3}^{2} + {3}^{2} } \\ = \sqrt{9 + 9} \\ = \sqrt{2 \times 9} \\ \therefore \: l= 3 \sqrt{2} \: ft \\ \\ total \: surface \: area \: of \: cone \\ = \pi \: r(l + r) \\ = 3.14 \times 3(3 \sqrt{2} + 3) \\ = 9.42 \times 3( \sqrt{2} + 1) \\ = 28.26 \times (1.414 + 1) \\ = 28.26 \times 2.414 \\ = 68.21964 \\ \approx \: 68.2 \: {ft}^{2}$

8 0

3 years ago

May I have some help with this?

madam [21]

Answer:

a. tanB= 3/2

Step-by-step explanation:

tanA= p/b =:2/3

For angle A,

p= 2

b=3

For angle B,

p = 3

b=2

So, TanB = 3/2

6 0

3 years ago