Answer:
Total number of pages in the book is 234.
Step-by-step explanation:
Let us assume that the total number of pages in the book = <em>x</em>
Now, it is given that Makaila read 44 pages yesterday.
Also, Makaila read two-third of the book today. As we have assumed that, there are a total of x number of pages in the book, so we can say that Makaila read two-third of <em>x </em>number of pages today.
Number of pages read by Makaila today = 
Now, it is also given that, Makaila read a total of 200 pages in the past two days.
∴ according to question,
Pages read yesterday + Pages read today = 200
⇒
⇒
⇒
⇒![132+2x=200\times3\;\;\;\;\;\;\;\;\;[On\;cross-multiplying]](https://tex.z-dn.net/?f=132%2B2x%3D200%5Ctimes3%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5BOn%5C%3Bcross-multiplying%5D)
⇒
⇒
⇒
⇒
∴ Total number of pages in the book = <em>x</em> = 234
= 16 + 49 - 3(11) - 4(10)
= 16 + 49 - 33 - 40
= -8
Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190



has a pvalue of 0.8944
X = 185



has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
The two-way table is attached.
We know that 63 people took the survey, and 22 of them were left-handed. This means that 63-22=41 of them are right handed.
Out of the 63 total, 37 are left brain dominant; this means that 63-37=26 are right brain dominant.
Of the 26 that are right brain dominant, 21 are right handed; this means 26-21=5 are left handed.
Of the 22 left-handed people, 5 are right brain dominant; this means 22-5 = 17 are left brain dominant.
Of the 37 left brain dominant people, 17 are left handed; this means 37-17=20 are right handed.