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Black_prince [1.1K]
2 years ago
11

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
1 answer:
kykrilka [37]2 years ago
3 0
The answer is B
\frac{5 \sqrt{13} }{13}
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The probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

<h3>What are some of the properties of Poisson distribution?</h3>

The Poisson distribution is a discrete probability distribution that describes the likelihood of a specific number of events occurring in a specified span of time or space, if these events occur at a constant mean rate and regardless of the time since the last occurrence.

Let X ~ Pois(λ)

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E(X) = λ = Var(X)

Since standard deviation is the square root (positive) of variance,

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The standard deviation of X = \sqrt{\lambda}

Its probability function is given by

f(k; λ) = Pr(X = k) =   \dfrac{\lambda^{k}e^{-\lambda}}{k!}

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We have to find the probability that on any day, the number of special orders sent out will be exactly 3. Therefore, the value of x will be 5.

Using the Poisson distribution,

P(x) = \dfrac{e^{-\lambda}\lambda ^x}{x!}\\\\P(5) =\dfrac{e^{-4.2}(4.2)^5}{5!}\\\\P(5) = 0.1633

Hence, the probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

Learn more about Poisson distribution here:

brainly.com/question/7879375

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