RFLP = Restriction fragment length polymorphismWe can say that an individual has a recombination when we see that in RFLP there are two bands. One in normal migration, and one in the pathologic migration.In generation III we can see it in individual 1, 3, 5, 7, 8, and 10. Any modification of the DNA sequences (mutation, addition, deletion) frequently rearranges the restriction sites. During the action of restriction enzymes, the size of the restriction fragments is then modified, and the fragments are then separated differently according to their size by electrophoresis: a polymorphism is observed.
Answer:
2. meiosis I only
Explanation:
During the zygotene stage of prophase-I of meiosis-I, homologous chromosomes synapse and are paired up. These paired homologous chromosomes are called bivalents. These paired homologous chromosomes align themselves at the equatorial plate of the cell during metaphase-I. Therefore, when observed through a microscope, cells are shown lined up two by two. During meiosis-II and mitosis, individual chromosomes with two sister chromatids are aligned at the cell's equator in metaphase.
Answer:
Tt - 2/4 = 1/2 or 50% Heterozygous TALL
tt - 2/4 = 1/2 or 50% Homozygous Dwarf
Explanation:
So let's make a Punnett for this so you can see what the outcome is yourself:
Tall is <u>dominant</u> - T
Dwarf is <u>recessive</u> - t
Heterozygous means that they have one of each allele. The genotype of one parent would be then Tt.
***It is heterozygous tall because Tall is a dominant trait so if it is accompanied by the recessive trait dwarf, then the Tall allele would mask it.
The other parent is a dwarf plant. The genotype would then be tt.
*** Now for a recessive trait to appear, it should not have a dominant trait mixed with it, which could mask it. The result then is homozygous recessive or homozygous Dwarf.
So now that we know the genotypes of the parent plants, we can put it into a Punnet:
t t
T Tt Tt
t tt tt
As you can see, out of the 4 outcomes we have:
Tt - 2/4 = 1/2 or 50% Heterozygous TALL
tt - 2/4 = 1/2 or 50% Homozygous Dwarf
Answer:
The correct answer is duodenum
Explanation:
Bile is a digestive enzyme that is secreted by the liver which is temporarily stored in the gall bladder and pancreatic enzyme is released by the pancreas. The bile is secreted to the small intestine through the common bile duct and the pancreatic duct joins the common bile duct just before ampulla of Vater which opens in the first intestinal portion which is duodenum.
So bile and pancreatic enzymes enters the duodenum region of the small intestine and after getting in the small intestine it digests the complex macromolecules into simpler and smaller form which can be absorbed through the intestinal epithelium.
