Given:
Work done, W = 5 J
Initial energy = 8J
Final energy = 30J
Let's determine if the work done have a positive or nrgative value.
Appy the equation for the first lae of thermodynamics:
Where:
U is the change in internal energy
Q is the added heat
W is the work done
To find the work done here, we have:
Rewrite the formula for W
Where:
ΔU = 30J - 8J = 22J
Q = 5J
Thus, we have:
Therefore, the work done here is -17J.
This means the work done in this scenario has a negative value.
ANSWER:
The work done in this scenario has a negative value
Answer: It prevents us from seeing most of the galactic disk with visible and ultraviolet light.
(hope this helps) :)
Answer:
* First fight the reaction time of the person, which is approximately 1/10 s, remember that the stopwatch does not stop alone
* Problems to synchronize when starting to measure the oscillation and end point of the oscilloscope, this error needs a good control system to be decreased.
*Effect of friction with air
Explanation:
In the measurements of the oscillatory movement in general, the most difficult magnitude of the measurement is the period, by reasoning
* First fight the reaction time of the person, which is approximately 1/10 s, remember that the stopwatch does not stop alone
* Problems to synchronize when starting to measure the oscillation and end point of the oscilloscope, this error needs a good control system to be decreased.
* Effect of friction with air
Answer:
Emec = 94050 [J]
Explanation:
In order to solve this problem, we must understand that all thermal energy is converted into mechanical energy.
The thermal energy can be calculated by means of the following expression.
where:
Q = heat [J]
Cp = specific heat of water = 4186 [J/kg*°C]
m = mass = 300 [g] = 0.3 [kg]
T_final = 95 [°C]
T_initial = 20 [°C]
Now we can calculate the heat, replacing the given values:
![Q=0.3*4180*(95-20)\\Q= 94050[J]](https://tex.z-dn.net/?f=Q%3D0.3%2A4180%2A%2895-20%29%5C%5CQ%3D%2094050%5BJ%5D)
Since all this energy must come from the mechanical energy delivered by the exercise bike, and no energy is lost during the process, the mechanical energy must be equal to the thermal energy.
![Q=E_{mec}\\E_{mec}=94050[J]](https://tex.z-dn.net/?f=Q%3DE_%7Bmec%7D%5C%5CE_%7Bmec%7D%3D94050%5BJ%5D)
Answer:
0 N/C
Explanation:
Parameters given:
The distance between 
and 
is
Electric field is given as
r = 15/2 = 7.5cm = 0.075m
The electric field at their midpoint due to is:
= 
The electric field at the midpoint due to is:
= 
The net electric field will be:
E = +
E = 
+ 
E = 0 N/C
