Answer:
0.88 cm
Explanation:
Initial length at 10°c, L = 23 m
Rise of temperature, Δt = 42 - 10 = 32°c
Coefficient of linear expansion of concrete, α = 12 x 10^(-6) per°c
Minimum spacing to be left = α L Δt
= 8.832 x 10^{-1} cm
= 0.88 cm
Note: I have a chosen a general value of 12 x 10^-6 per deg c for coefficient of expansion of concrete. However, please refer to the value given in your text book and substitute it for an accurate answer.
Answer:
abcdefghijklmnopqrstuvwxyz
Answer:
a) , b) , c)
Explanation:
a) The linear acceleration of the watermelon seed is:
b) The watermelon seed is experimenting a centrifugal acceleration. The coefficient of static friction between the seed and the turntable is calculated by the Newton's Laws:
c) Angular acceleration experimented by the turntable is:
The tangential acceleration experimented by the watermelon seed is:
The linear acceleration experimented by the watermelon seed is:
The minimum coefficient of static friction is:
Answer:
d = v² / (2μ g)
Explanation:
In the work relationship is equal to the variation of energy,
W = ΔEm
The work is defined by
W = F. d = F d cos θ
In this case the outside is the force of friction, which always opposes
to the movement, so the angle is 180 °
W = - fr d
The force of friction can be found with Newton's second law
fr = μ N
Y Axis
N- W = 0
N = mg
fr = μ m g
We substitute in the expression of work
W = - μ mg d
Now we use the relationship of work and energy
-μ mg d = 0 -½ m v²
d = v² / (2μ g)