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ICE Princess25 [194]
2 years ago
7

Label the sound wave-   amplitude, wavelength,  crest, trough​

Physics
1 answer:
enot [183]2 years ago
7 0

Answer:

A - Crest,  B - amplitude,  C - wavelength,  D - trough

Explanation:

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After an avalanche, a huge block of stone slid down a mountain and landed in the middle of a road. People in the nearby town had
jeka94

Answer:

Option (C)

Explanation:

From Newton's law of inertia, an object at rest tends to be at rest until there is an external force applied to it.

In the given question, the rock block that fell on the road due to the avalanche contains high mass and high inertia. Due to which the block was not able to move aside. <u>The amount of energy required to push the block aside should be more than the mass of the block</u>. So the block has high inertia value and it will need more force than its inertia value in order to move the block of rock towards the side of the road.

Thus, the correct answer is option (C).

4 0
3 years ago
2. A construction consultant may be responsible for
Brrunno [24]

This is a tricky one but on my part I'd have to say depending on the contract A,B,C.

3 0
3 years ago
Brainliest if right.
jeka57 [31]

Answer:

the third law (for every action there is an equal and opposite reaction).

Explanation:

The skateboarder pushes backwards on the road (that is he applies a force on the road in a direction opposite the direction of intended motion). By Newton's third law, this action of the skateboarder causes an equal reaction of the road on the skateboarder in the opposite direction. Newton's third law states that action and reaction are equal but opposite in direction. So, the road in response to this backward force pushes the skateboarder in the forward direction causing the skateboarder and the skateboard to move in the forward direction.

5 0
2 years ago
A projectile is launched from ground level with an initial speed of 47 m/s at an angle of 0.6 radians above the horizontal. It s
Zarrin [17]

Answer:

30.67m

Explanation:

Using one of the equations of motion as follows, we can describe the path of the projectile in its horizontal or vertical displacement;

s = ut ± \frac{1}{2} at^2               ------------(i)

Where;

s = horizontal/vertical displacement

u = initial horizontal/vertical component of the velocity

a = acceleration of the projectile

t = time taken for the projectile to reach a certain horizontal or vertical position.

Since the question requires that we find the vertical distance from where the projectile was launched to where it hit the target, equation (i) can be made more specific as follows;

h = vt ± \frac{1}{2} at^2               ------------(ii)

Where;

h = vertical displacement

v = initial vertical component of the velocity = usinθ

a = acceleration due to gravity (since vertical motion is considered)

t = time taken for the projectile to hit the target

<em>From the question;</em>

u = 47m/s, θ = 0.6rads

=> usinθ = 47 sin 0.6

=> usinθ = 47 x 0.5646 = 26.54m/s

t = 1.7s

Take a = -g = -10.0m/s   (since motion is upwards against gravity)

Substitute these values into equation (ii) as follows;

h = vt - \frac{1}{2} at^2

h = 26.54(1.7) - \frac{1}{2} (10)(1.7)^2

h = 45.118 - 14.45

h = 30.67m

Therefore, the vertical distance is 30.67m        

7 0
3 years ago
How much work is needed to pump all the water out of a cylindrical tank with a height of 10 m and a radius of 5 m
balu736 [363]

Answer:

Explanation:

volume of water being lifted

= π r² h , where r is radius of cylinder and h is height of cylinder

= 3.14 x5² x 10

= 785 m³

mass of water = 785 x 10³ kg

mass of this much of water is lifted so that its centre of mass is lifted by height

10 / 2 = 5m .

So work done = mgh , m is mass of water , h is displacement of centre of mass and g is acceleration due to gravity

= 785 x 10³ x 9.8 x 5

= 38.465 x 10⁶ J  

6 0
3 years ago
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