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r-ruslan [8.4K]

2 years ago

14

A student took a calibrated 200.0 gram mass, weighed it on a laboratory balance, and found it read 186.5 g. What was the student

’s percent error?

1 answer:

snow_lady [41]2 years ago

7 0

Answer:

The original or accepted value for the percent by mass of water in a hydrate = 36%

Percen by mass of water in the hydrate determined by the student

in the laboratory = 37.8%

So the difference between the actual and the percent by mass in water determined by student = (37.8 - 36.0)%

= 1.8%

So the percentage of error made by the student = (1.8/36) * 100 percent

= (18/360) * 100 percent

= ( 1/20) * 100 percent

= 5 percent

So the student makes an error of 5%. Option "1" is the correct option.

Explanation:

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Nimfa-mama [501]

Complete Question

The compete question is shown on the first uploaded question

Answer:

The speed is $v = 350 \ m/s$

Explanation:

From the question we are told that

The distance of separation is d = 4.00 m

The distance of the listener to the center between the speakers is I = 5.00 m

The change in the distance of the speaker is by $k = 60 cm = 0.6 \ m$

The frequency of both speakers is $f = 700 \ Hz$

Generally the distance of the listener to the first speaker is mathematically represented as

$L_1 = \sqrt{l^2 + [\frac{d}{2} ]^2}$

$L_1 = \sqrt{5^2 + [\frac{4}{2} ]^2}$

$L_1 = 5.39 \ m$

Generally the distance of the listener to second speaker at its new position is

$L_2 = \sqrt{l^2 + [\frac{d}{2} ]^2 + k}$

$L_2 = \sqrt{5^2 + [\frac{4}{2} ]^2 + 0.6}$

$L_2 = 5.64 \ m$

Generally the path difference between the speakers is mathematically represented as

$pD = L_2 - L_1 = \frac{n * \lambda}{2}$

Here $\lambda$ is the wavelength which is mathematically represented as

$\lambda = \frac{v}{f}$

=> $L_2 - L_1 = \frac{n * \frac{v}{f}}{2}$

=> $L_2 - L_1 = \frac{n * v}{2f}$

=> $L_2 - L_1 = \frac{n * v}{2f}$

Here n is the order of the maxima with value of n = 1 this because we are considering two adjacent waves

=> $5.64 - 5.39 = \frac{1 * v}{2*700}$

=> $v = 350 \ m/s$

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3 years ago

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Answer:

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Explanation:

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$Q^2=0.250\times 10^{-12}$

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