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Yanka [14]
3 years ago
10

If the amplitude of the resultant wave is twice as great as the amplitude of either component wave, and this wave exhibits reinf

orcement, the component waves must
Physics
2 answers:
worty [1.4K]3 years ago
8 0
<span>If the amplitude of the resultant wave is twice as great as the amplitude of either component wave, and this wave exhibits reinforcement, the component waves must BE IN PHASE WITH EACH OTHER</span>
dimaraw [331]3 years ago
7 0
This question seems to really be incomplete. You must include the options but fortunately I have already encountered this problem.
Here are the choices:

<span>A. have a different frequency than the resultant wave.
B. be in phase with each other.
C. be traveling in the opposite direction of the resultant wave.
D. have a different wavelength than the resultant wave

The correct answer is letter B. be in phase with each other</span>
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One negative change you may encounter as a student or an employee​
matrenka [14]

Answer:

you may get bullied or teased for being a differrent race, ethnic.

7 0
3 years ago
Read 2 more answers
A race car accelerates from 0 m/s to 30.0 m/s with a displacement of
worty [1.4K]

Answer:

4. 10.0 m/s²

Explanation:

I) if initial velocity is 'v₀', the final velocity is 'v', the accelaration is 'a', the distance is 'L' and elapsed time if 't', then:

1. \ a=\frac{v-v_0}{t};

2. \ L=\frac{at^2}{2}.

II) using these two equations after substitution v₀=0; v=30 and L=45:

\left \{{{45 =\frac{at^2}{2}} \atop {a=\frac{30-0}{t} }} \right.

\left \{ {{at^2=90} \atop {at=30}} \right. \  \ \left \{ {{a=10} \atop {t=3}} \right. => \ a=10\frac{m}{s^2}

6 0
3 years ago
Visible light with a wavelength of 480 nm appears Question 33 options:
AlladinOne [14]
It would appear as blue

5 0
3 years ago
Light propagate faster through medium “a” than medium “b”
dangina [55]

1) Medium "b" has more optical density

2) Light must hit the interface between the two mediums perpendicularly

Explanation:

1)

Refraction occurs when light propagates from a medium into a second medium.

The optical density of a medium is given by its index of refraction, which is defined as:

n=\frac{c}{v}

where

c is the speed of light in a vacuum

v is the speed of light in a medium

Higher index of refraction means higher optical density, and light propagater slower into a medium with higher optical density.

In this problem, light propagates faster through medium "a" than medium "b": this means that medium "a" has lower refractive index of medium "b", and so "b" has more optical density.

2)

We can answer this part by referring to Snell's law, which gives the relationship between the direction of the incident ray and of the refracted ray when light passes through the interface between two media:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1, n_2 are the index of refraction of the two mediums

\theta_1, \theta_2 are the angle of incidence and of refraction (the angle that light makes with the normal to the surface in medium 1 and medium 2)

Here we want the direction of propagation of the light ray not to change: this means that it must be

sin \theta_1 = sin \theta_2 (1)

However, here we have two mediums "a" and "b" with different index of refraction, so

n_1\neq n_2

Therefore the only angle that can satisfy eq.(1) is

\theta_1 = \theta_2 = 0

So, the light must hit the surface perpendicular to the interface between the two mediums.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

3 0
3 years ago
An 8.00- W resistor is dissipating 100 watts. What are the current through it and the difference of potential across it?
hjlf

Answer:

I= 3.5 amps

Explanation:

Step one:

given data

rating of resistor R= 8 ohms

power P= 100W

Required

The current I

Step two

Yet this power is also given by

P = I^2R

make I subject of the formula we have

I= \sqrt{\frac{P}{R} }

substitute

I= \sqrt{\frac{100}{8} }\\\\I=\sqrt{12.5}\\\\I= 3.5 amps

8 0
3 years ago
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