<span>0.0292 moles of sucrose are available.
First, lookup the atomic weights of all involved elements
Atomic weight Carbon = 12.0107
Atomic weight Hydrogen = 1.00794
Atomic weight Oxygen = 15.999
Now calculate the molar mass of sucrose
12 * 12.0107 + 22 * 1.00794 + 11 * 15.999 = 342.29208 g/mol
Divide the mass of sucrose by its molar mass
10.0 g / 342.29208 g/mol = 0.029214816 mol
Finally, round the result to 3 significant figures, giving
0.0292 moles</span>
To get the molecules contained in liquid ethanol, we multiply the density to the given volume, that is equal to 0.789 g ethanol. In this case, we divide by molar mass and multiply by the constant, Avogadro's number. The answer is 1.033 x 10^22 molecules.
Answer:
9√3
Explanation:
Given that :
UV = 18
Angle V = 60°
To obtain the measure of UW = v
Using trigonometry :
Sinθ = opposite / hypotenus
Sinθ = UW / 18
θ = 60°
sin60° = UW / 18
Sin 60° = √3/2
√3 /2 = UW / 18
UW = 18 * √3/2
UW = 9 * √3
UW = 9√3
The expected final temperature of the block, given that 586 J of heat were added to it is 55.5 °C
<h3>How to determine the final temeprature</h3>
We'll begin by obtaining the change in the temperature of the block. This can be obtained as follow:
- Specific heat capacity of block (C) = 0.240 J/gºC
- Heat added (Q) = 586 J
- Mass of block (M) = 80.0 g
- Change in temperature (ΔT) =?
Q = MCΔT
Divide both sides by MC
ΔT = Q / MC
ΔT = 586 / (80.0 × 0.240)
ΔT = 586 / 19.2
ΔT = 30.5 °C
Finally, we shall determine the final temperature of the block. This can be obtained as follow:
- Initial temperature (T₁) = 25 °C
- Change in temperature (ΔT) = 30.5 °C
- Final temperature (T₂) = ?
ΔT = T₂ – T₁
30.5 = T₂ – 25
Collect like terms
T₂ = 30.5 + 25
T₂ = 55.5 °C
Thus, from the calculation made above, we can conclude that the final temperature is 55.5 °C
Learn more about heat transfer:
brainly.com/question/14383794
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Answer: 1 mole of 
has the greatest mass.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP , contains avogadro's number 
of particles and weighs equal to the molecular mass of the substance.
1 mole of has a mass of 40 g.
1 mole of 
has a mass of 28 g
1 mole of 
has a mass of 32 g
1 mole of 
has a mass of 16 g.
1 mole of 
has a mass of 30 g.
Thus the greatest mass is of 1 mole of
