How many molecules of liquid ethanol (CH3H2OH) are in 1.00 mL of ethanol, given its density is 0.789 g/mL?

1 answer:

7 0

To get the molecules contained in liquid ethanol, we multiply the density to the given volume, that is equal to 0.789 g ethanol. In this case, we divide by molar mass and multiply by the constant, Avogadro's number. The answer is 1.033 x 10^22 molecules.

You might be interested in

What is the molecular shape of HCN

Rufina [12.5K]

Linear Hydrogen Cyanide. In this example, HCN, the Lewis diagram shows carbon at the center with no lone electron pairs. The carbon and nitrogen are bonded through a triple bond which counts as "one electron pair". Hence the molecule has two electron pairs and is linear.

3 0

3 years ago

How many moles of h are in 0.73 mole of c6h10s

Mnenie [13.5K]

Answer:

7.3 mole

Explanation:

1 C6H10S gives 10H

0.73 mole of C6H10S gives X mole of Hydrogen

X= 0.73×10=7.3mole

7 0

4 years ago

Calculate the pH at of a 0.10 Msolution of anilinium chloride . Note that aniline is a weak base with a of . Round your answer t

notsponge [240]

The question is incomplete, here is the complete question:

Calculate the pH at of a 0.10 M solution of anilinium chloride $(C_6H_5NH_3Cl)$ . Note that aniline $(C6H5NH2)$ is a weak base with a $pK_b$ of 4.87. Round your answer to 1 decimal place.