From the ideal gas law, PV = nRT, we can rearrange the equation to solve for T given the other parameters.
T = PV/nR
where P = 0.878 atm, V = 1.20 L, n = 0.0470 moles, and R = 0.082057 L•atm/mol•K. Plugging in our values, we obtain the temperature in Kelvin:
T = (0.878 atm)(1.20 L)/(0.0470 mol)(0.082057 L•atm/mol•K)
T = 273 K
So, the second answer choice would be correct.
Multiply the atomic weight
Answer:
6.76 moles.
Explanation:
2CO(g)+O2 (g) =2CO2(g)
When 2 CO mols were reacted with excess O2 then 2 mols of CO2 is created.
Therefore if 6.76 moles reacted, same number of CO2 will be created.