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Anika [276]
3 years ago
13

A 2.0-kg pistol fires a 1.0-g bullet with a muzzle speed of 1000 m/s. The bullet then strikes a 10-kg wooden block resting on a

horizontal frictionless surface. The block and the embedded bullet then slide across the surface. The explosive charge in the pistol acts for 0.001 s. What is the average force exerted on the bullet while it is being fired
Physics
1 answer:
Andreyy893 years ago
4 0

Answer:

1000 N

Explanation:

An impulse results in a change of momentum

FΔt = mΔv

F = 0.001 kg(1000 - 0) m/s / 0.001 s = 1000 N

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3 years ago
Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?
Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

KE_1 = \dfrac{1}{2}mv^2

2000= \dfrac{1}{2}mv^2........(1)

now, speed of the car is doubled

v' = 2 v

KE_2 = \dfrac{1}{2}mv'^2

KE_2 = \dfrac{1}{2}m(2v)^2

from equation (1)

KE_2 = 4\times \dfrac{1}{2}m(v)^2

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8 0
2 years ago
If a weightlifter lifts a 286 kg mass 0.25 meters above his head, how much PEg does the mass have?
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Answer:

Change in potential energy is 700.7 J.

Explanation:

Given:

Mass of the object is, m=286 kg

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Acceleration due to gravity is, g=9.8 m/s²

We know that for a mass m raised to a height h, the change in potential energy is given as:

\Delta PE=mgh, where, \Delta PE\rightarrow \textrm{Change in Potential Energy}

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3 years ago
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