Answer:
2.57 seconds
Explanation:
The motion of the ball on the two axis is;
x(t) = Vo Cos θt
y(t) = h + Vo sin θt - 1/2gt²
Where; h is the initial height from which the ball was thrown.
Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²
We want to find the time t at which y(t) = h
Therefore;
y(t) = h + Vo sin θt - 1/2gt²
Whose solutions are, t = 0, at the beginning of the motion, and
t = 2 Vo sinθ/g
= (2 × 22 × sin 35°)/9.81
= 2.57 seconds
Applying Newton's Second Law of Motion, the acceleration of the ball is 16.8 
<u>Given the following data:</u>
- Acceleration due to gravity = 9.8

To find ball's acceleration, we would apply Newton's Second Law of Motion:
First of all, we would determine the net force acting on the ball.

× 
Downward force = 4.9 N

Net force = 8.4 N
Mathematically, Newton's Second Law of Motion is given by this formula;

<em>Acceleration = 16.8 </em>
<em />
Therefore, the acceleration of the ball is 16.8 
Read more here: brainly.com/question/24029674
Complete Question
The complete question is shown on the first uploaded image
Answer:
The strain experienced by the specimen is 0.00116 which is option A
Explanation:
The explanation is shown on the second uploaded image
The given question is incomplete. The complete question is as follows.
The block has a weight of 75 lb and rests on the floor for which
= 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.
Determine the output of the motor at the instant
.
Explanation:
We will consider that equilibrium condition in vertical direction is as follows.

N - W = 0
N = W
or, N = 75 lb
Again, equilibrium condition in the vertical direction is as follows.

= 0

= 
= 30 lb
Now, the equilibrium equation in the horizontal direction is as follows.



or, T = 
= 
= 
= 17.32 lb
Now, we will calculate the output power of the motor as follows.
P = Tv
= 
= 
= 0.189 hp
or, = 0.2 hp
Thus, we can conclude that output of the given motor is 0.2 hp.