Finding how much fence Angela needs to put in garden can be found by finding the perimeter of the walls that are not blocked by anything. For example, the house is blocking one side of the garden.
We can write this expression as: 2x + 2x + x
After solving we get 5x.
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Answer:
The total in the account after 10 years would be: $14,190.68
Step-by-step explanation:
Recall the formula for continuous compounding:
![A=P\,e^{r\,t}](https://tex.z-dn.net/?f=A%3DP%5C%2Ce%5E%7Br%5C%2Ct%7D)
where "A" is the accrued value after t years (what we need to find), "P" is the principal invested (in our case $10,000), "r" is the interest rate in decimal form (in our case r = 0.035), and "t" is the time in years (in our case t = 10). Therefore the formula becomes:
![A=P\,e^{r\,t}\\A=10000\,\,e^{0.035\,*\.10}\\A=14190.68](https://tex.z-dn.net/?f=A%3DP%5C%2Ce%5E%7Br%5C%2Ct%7D%5C%5CA%3D10000%5C%2C%5C%2Ce%5E%7B0.035%5C%2C%2A%5C.10%7D%5C%5CA%3D14190.68)
Therefore the total in the account after 10 years would be: $14,190.68
Answer:
45 sweets.
Step-by-step explanation:
6:2:1
To solve how many Jim and Dan has I did 6 x n and 1 x n until the difference of the two numbers equaled 25.
6 x 5 = 30
1 x 5 = 5
30 - 5 = 25.
So, Jim as 30 candy and Dan has 1. How much does David have?
Just do the same thing but with 2 x n:
2 x 5 = 10.
Now add them together:
30 + 10 + 5 = 45.
Therefore, 45 sweets!
The answer is going to be 250
Answer:
$20 on each cat and $40 on each dog
Step-by-step explanation:
Call the amount spent on each, cat, x and let the amount spent each dog = y = 2x
So we have the following constraints:
y = 2x (1)
164(x) + 24y <= 4240 (2)
Substituting (1) into 2 for y, we have
164x + 24(2x) <= 4240 simplify
212x <= 4240 divide both sides by 212
x<= $20 on each cat
And y = 2(20) = $40 on each dog
So she can spend $20 on each cat and $40 on each dog