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mario62 [17]
3 years ago
9

Pleaseeeeee help I Will mark brainliest

Chemistry
1 answer:
Serjik [45]3 years ago
3 0
Omg I really really done know I just want point so ✌️ out
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Which is a property of all atoms?
Thepotemich [5.8K]
B. a nucleus with a positive charge.
4 0
3 years ago
Read 2 more answers
O2- is the Lewis ______ in the following reaction
matrenka [14]

O^{2-} is the Lewis base in the following reaction:

SO_3(g) + O^{2-}(aq)   →  SO_4^{2-}(aq)

<h3>What is lewis base? </h3>

Lewis base is a species that donates an electron pair.

In the above-given chemical equation, the O^{2-}is the lewis base which is donating an electron pair to the central atom of SO_3 to form SO_4^{-2}.

Hence, O^{2-} is the Lewis base in the following reaction:

SO_3(g) + O^{2-}(aq)   →  SO_4^{2-}(aq)

Learn more about the lewis base here:

brainly.com/question/15570523

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3 0
1 year ago
Heredity is defined as
AnnyKZ [126]

Answer:

B.

the passage of genetic instructions from one generation to the next generation.

These are called genes. One mate reporduces with another made and the genetic buildup merges 50 % and 50% with genetics(if it's meiosis), or DNA codes from the parents to the offspring that then possess some of the genes. That shows heridity.

8 0
3 years ago
A material has a density of 8.9 g/cm^3. You have 3 grams of the substance. How much space does it take up? a. 0.3cm3 b. 3.0 cm3
My name is Ann [436]
D = m/ V

8.9 = 3 / V

V = 3 / 8.9

V = 0.3 cm³

Answer A

hope this helps!
6 0
3 years ago
Read 2 more answers
Question 4 point
Ronch [10]

Answer:

5393.4gH_2O

Explanation:

Hello there!

In this case, for the described chemical reaction, we can write:

CH_4+2O_2\rightarrow CO_2+2H_2O

Thus, by considering the 1:2 mole ratio of methane to water, and the molar mass of the latter (18.02 g/mol), the following is useful to calculate the mass of water that is produced:

149.65molCH_4*\frac{2molH_2O}{1molCH_4} *\frac{18.02gH_2O}{1molH_2O}

Which is equal to:

5393.4gH_2O

Which is not among the choices.

Regards!

5 0
3 years ago
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