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Elenna [48]
3 years ago
6

Which of these elements has four total electrons in its outer p orbitals?

Chemistry
2 answers:
tia_tia [17]3 years ago
7 0

The element that has four total electrons in its outer P orbitals is

Sulphur (s) (answer D)

Sulphur is in group 16 and period 3 in the periodic table therefore Sulphur is in atomic number 16.

Sulphur (S) electronic configuration is 1S2 2S2 2P6 3S2 3P4 or [Ne] 3S2 3P4 therefore the 3P4 subshell of sulphur has only 4 electrons.

ycow [4]3 years ago
5 0
<span>SulphurS 161s22s22p63s23p<span>4</span></span>

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A sample of a substance was determined and contained 1.0g of mg and 1.75g of o. what is the empirical formula? (10 pts)
Juliette [100K]
<span>Total mass = 2.75g Mass % of Mg = 1.0g x 100/2.75g = 36.36 % Mass % of O = 1.75g x 100/2.75g = 63.64 % Mol of Mg = 36.36/24 = 1.515 Mol of O = 63.64/16 = 3.977 Ratio of Mol of Mg and O in the substance = (1.515 : 3.977) x 2 = 3 : 8 The empirical formula of substance is Mg3O8</span>
7 0
3 years ago
Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
pochemuha

Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

Now we have to calculate the moles of HCO_3^-.

Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = 37^oC=273+37=310K

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

V=0.51411L=514.11ml

Therefore, the volume of CO_2 will be, 514.11 ml

6 0
3 years ago
Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.
Marrrta [24]

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

Explanation:

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        Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

  • Type  of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

  • Chromium(Cr)
  • Cobaltous Chloride (CoCl_2)

Products formed in the reaction are -

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Hence, the chemical reaction is as follows -

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For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

3 0
3 years ago
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A) solid
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5 0
3 years ago
What is the mass number of an atom or ion with three protons, three neutrons, and three electrons?.
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Answer:

the mass number of the atom or ion is 6

5 0
3 years ago
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