1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BigorU [14]
3 years ago
11

Gases and particles which are put into the air or emitted by various sources are called __________. photochemical smog emissions

carbon monoxide radon (geology)
Chemistry
1 answer:
Leto [7]3 years ago
7 0
I would say the answer is emissions. These are the particles that are not supposed to be present in air but due to the production of different substances from humans daily activities these substances go with the air we breath. Hope this helped.
You might be interested in
I am stuck... Chemistry is the worst and anything is appreciated!
Soloha48 [4]
I think it is 110 mL but I’m not totally sure.
8 0
3 years ago
Read 2 more answers
Shown below is a balance. Based on this instrument, identify from the following list all the statements that are true if you wer
kirill115 [55]

From the image shown, the uncertainty in the weighing balance extends to the hundredth place.

<h3>What is a balance?</h3>

A balance is any device that is used for measuring the mass or weight of an object. The balance is a necessary instrument in every laboratory.

Looking at the image shown, the following are true;

  • the uncertainty is in the hundredth place.
  • a mass that falls between 1 gram and 9 grams measured on this balance will always have 3 significant figures.

Learn more about weighing balance: brainly.com/question/8902159

5 0
2 years ago
A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.
Alexxandr [17]

<u>Answer:</u> The empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

<u>Explanation:</u>

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = \frac{0.313}{0.078}=4.01\approx 4

For Hydrogen  = \frac{0.316}{0.078}=4.05\approx 4

For Oxygen  = \frac{0.078}{0.078}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is C_4H_4O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

n=\frac{130g/mol}{68g/mol}=1.9\approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2

Hence, the empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

4 0
3 years ago
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonatio
Over [174]

Answer:

Most substituted alkene is produced as a major product

Explanation:

  • Dehydration of 3-methyl-2-butanol proceeds through E1 mechanism to form alkenes.
  • Most substituted alkene is produced as major product because of presence of highest number of hyperconjugative hydrogen atoms corresponding to the produced double bond (Saytzeff product).
  • Here, a H-shift also occurs in one of the intermediate step during dehydration to produce more stable tertiary carbocation.
  • Reaction mechanism has been shown below.

4 0
3 years ago
If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog
9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

11 nanomoles .....................

(11 x 56) / 1 .10^9 nanomoles = 6.16 x 10^-7 gr

Let's convert

6.16 x 10^-7 gr x 1 .10^9 = 616 ngr

8 0
3 years ago
Other questions:
  • Convert 1.25 kg into grams
    11·1 answer
  • What is the total number of elements in group 17 that are gases at room temperature and standard pressure?
    14·1 answer
  • A bag of sand and a bag of feathers can have the same density if they have different:
    12·1 answer
  • Need help asap!!!!! Plz
    6·1 answer
  • According to the kinetic molecular theory what happens to a liquid then it is transferred from one container to another
    14·2 answers
  • A tool used to measure weight
    13·2 answers
  • Chloral hydrate (C2H3Cl3O2) is a drug formerly used as a sedative and hypnotic.
    9·1 answer
  • List 5-6 facts about earths interior.
    14·1 answer
  • Which describes a similarity between abiotic and biotic Which describes a similarity between abiotic and biotic factors?
    11·2 answers
  • Two different gases are stored in separate closed containers. If both gases have a temperature of 50°C, which statement is true?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!