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3 years ago

5% commission rate of 14.98

Mathematics

1 answer:

Arisa [49]3 years ago

7 0

Answer: If you mean 5% of $14.98, it is $0.75 75 cents

If you mean 14.98 represents a 5% commission on what sale amount

The sale amount was $299.60

Step-by-step explanation:

Change the percent to a decimal and multiply by the sale amount.

0.05 × 14.98 = .749 Round to .75

If 14.98 is the 5% commission, divide 14.98/.05= 299.60

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According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

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3 years ago

If h(x) = -2x - 10, find h(-4)

Lady bird [3.3K]

$- 2( - 4) - 10 \\ 8 - 10 \\ = - 2$

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3 years ago

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choli [55]

Answer:

VA(t) =vB(t)-50

Step-by-step explanation:

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The amount of money raised at a charity fundraiser is directly proportional to the number of attendees. The amount of money rais

sattari [20]

Answer:

a. M=20A

b. k=20

c. $1200

Step-by-step explanation:

Direct proportions

Two variables are proportional if one of them is the other by a real number. That real number is called the Constant of proportionality. If x and y are proportional, then

y=kx, where k is the constant of proportionality.

The question describes the relationship between the amount of money raised at a charity fundraiser and the number of attendees. If they have five attendees, they raise $100

Let's call A the number of attendees and M the amount of money raised, and

M=kA

We know that M=100 when A=5, so

100=k(5)

This means that

k=20

The equation for the amount raised at the charity event is

M=20A

The constant of variation is k=20

c. If there are 60 attendees (A=60), then

M=(20)(60)=$1200

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3 years ago

Please help ASAP! I’ll give brainliest:))

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Answer with explanation:

After dilation about the origin(0,0) with the scale factor of 'k" , the image of the original point (x,y) becomes (kx,ky)

From the given graph, the coordinates of point C = (0,6) [Since it lies on y-axis , the x-coordinate is zero]

After a dilation about the origin(0,0) with the scale factor of $\dfrac{1}{2}$ , the new point will be $(\dfrac{1}{2}\times0,\dfrac{1}{2}\times6)=(0,3)$

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