Q: "The density of material at the center of a neutron star is approximately 1.00 × 10¹⁸ kg/m3. What is the mass of a cube of this material that is 1.76 microns on each side. (One micron is equal to 1.00 × 10-6 m.)"
Answer:
5.452 kg
Explanation:
Density: This can be defined as the ratio of the mass of a substance to its volume. The S.I unit of density is kg/m³.
Mathematically, Density can be represented as
D = M/V
M = D×V ............................ Equation 1
Where D = density of the material, M = mass of the material, V = volume of the cube of the material,
But
V = L³
Where L = Length of the cube.
If 1 micron = 1.00×10⁻⁶ m,
Then, 1.76 microns = 1.76×10⁻⁶ m
Therefore L = 1.76×10⁻⁶ m
V = (1.76×10⁻⁶ )³
V = 5.452×10⁻¹⁸ m³
Given: D = 1.0×10¹⁸ kg/m³, and V = 5.452×10⁻¹⁸ m³
Substitute into equation 1
M = 1.0×10¹⁸×5.452×10⁻¹⁸
M =5.452 kg.
Hence the mass of the cube material = 5.452 kg
